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Creating a query to show all records from one table plus those that are linked from another

Posted on 2016-10-19
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Last Modified: 2016-10-19
I think my requirement should be quite simple, but just cannot seem to figure it out.

I have two related tables - Drivers and Journeys.
I am trying to construct a query that will list ALL drivers and then details of their future [date>=Date()] journeys if they have any.

Maybe like this....
Joe Bloggs
John Smith - Journey1
John Smith - Journey2
Jack Green
Jim Black - Journey3
Fred White - Journey4
Fred White - Journey5
etc etc...

All my attempts so far will only list drivers if they have a journey.

Hope someone can give me a nudge in the right direction.

Regards
Richard
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Question by:rltomalin
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3 Comments
 
LVL 47

Accepted Solution

by:
Dale Fye (Access MVP) earned 500 total points
ID: 41849890
Try something like:

Selecte Drivers.*, J.*
FROM Drivers
LEFT JOIN (
SELECT Journeys.* FROM Journeys
WHERE [Date] > Date()
) as J ON Drivers.DriverID = J.DriverID
0
 
LVL 47

Expert Comment

by:Dale Fye (Access MVP)
ID: 41849895
to expand on the previous comment,  in order to get all of the drivers, you have to use a LEFT Join to the Journeys table, but once you assign a criteria to the Journeys table, you end up losing all of the drivers who don't have future journeys.  You might also be able to do:

Selecte Drivers.*, Journeys.*
FROM Drivers
LEFT JOIN Journeys ON Drivers.DriverID = Journeys.DriverID
WHERE (Journeys.[Date] IS NULL) OR (Journeys.[Date] > Date())
0
 

Author Closing Comment

by:rltomalin
ID: 41850214
Hi Dale
The first option works fine - thanks very much.
The second option was similar to my attempts, where the journey criteria limited the list to drivers with journeys.

I think I can work with the first option - will have to build on it now.

Regards
Richard
0

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