SQL Find correct record using ;WITH

Using SQL  ;with , I need to only find the latest payment record with the highest payment amount for a customer.
I marked with a *, the records I need to be selected.

I will then take the With data and update another table.

Filea

Cust          Date                AMT
12345       2016/10/03   263,000
12345       2016/10/06   147,000
12345       2016/09/23    563,000  
12345       2016/10/06   153,000  *
12345       2016/10/06     99,000
23456       2016/08/02     15,000
23456       2016/09/13     11,000  *
456789     2016/10/10      66,300 *
564789     2016/03/12      65,000
564789     2016/03/12      65,500 *
etc...
thayduckProgrammer AnalystAsked:
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Jim HornConnect With a Mentor Microsoft SQL Server Developer, Architect, and AuthorCommented:
Explain why the ;With is part of the requirement.

Give this a whirl..
;with cte as ( 
   SELECT Cust, Date, AMT, 
      ROW_NUMER() OVER (PARTITION BY Cust ORDER BY Date DESC, AMT DESC) as rank_order
   FROM YourTable ) 
SELECT * FROM cte WHERE rank_order= 1 ORDER BY Cust

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< edited after original post to reflect correct answer >
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thayduckProgrammer AnalystAuthor Commented:
Your code executes but does not get the correct data for every customer.
For customer 144840, you got 2016/10/06 13,410 but it should have been 2016/10/06  251,578.

I will take that CTE file and update something with it.
With.PNG
WITH1.PNG
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
>For customer 144840, you got 2016/10/06 13,410 but it should have been 2016/10/06  251,578.
You're going to have to speak to the sample data in the original question.  Keep in mind that experts here cannot connect to your data source(s) and run queries, so we are completely dependant on what you post and can only make educated guesses based on that.
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thayduckProgrammer AnalystAuthor Commented:
Sorry, that was just a example so you knew that it was not working right.
The samples I sent you all came back correct.

I made a small change (to your code)  below and that seemed to fix it.

changed lastamt  to  lastamt DESC

Now they all look right as far as I can see.

Thanks for your quick response...
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thayduckProgrammer AnalystAuthor Commented:
Your code was actually  AMT (that is what I called it in my example) , I changed to AMT DESC.
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Jim HornMicrosoft SQL Server Developer, Architect, and AuthorCommented:
>changed lastamt  to  lastamt DESC
Doh.  My bad, you are correct.  Max amount woud be DESC.
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thayduckProgrammer AnalystAuthor Commented:
Thanks again for the very quick response.
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