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MS Access Image Control Split database display image on focus refresh or requery help!

I have a split database and I have a image control that when I click onto the next record the image doesn't requery or refresh to the new image.

This is my Forms On Current Code:

Private Sub Form_Current()
    
    Private Sub Form_Current()
    Call SetFormAllowAdditions(Me!sbfrmProducts.Form, 4)
    
    On Error GoTo ExitProc
    Dim ImagePath As String
    
   
    ImagePath = GetProductImageFilePath & Forms!frmSkusEntry!sbfrmProductImages.Form!ProductImageFileNm

    If Len(Forms!frmSkusEntry!sbfrmProductImages.Form!ProductImageFileNm) > 0 And Len(Dir(ImagePath)) > 0 Then
        Image126.Picture = ImagePath
    Else
        Image126.Picture = ""
    End If
    
ExitProc:
    Exit Sub
ErrProc:
    Select Case Err.Number
        Case Else
            Resume ExitProc
    End Select
End Sub

Public Function GetProductImageFilePath() As String
    GetProductImageFilePath = GetDBPath & "images\"
End Function


    Public Function GetDBPath() As String
    GetDBPath = Replace(CurrentDb.TableDefs("Assemblies").Connect, ";DATABASE=", "")
'Remove db name
GetDBPath = Left(GetDBPath, InStrRev(GetDBPath, "\"))

End Function

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ADD IMAGE BUTTON BROWSE TO FILE AND GET FILENAME CODE:

Public Function AddLocalImagePath() As Variant
Dim strImagePath As String

    strImagePath = GetFile_Browse
    
    If Me.NewRecord Then
        Me!ProductImageLocalPath = strImagePath
         Me!ProductImageFileNm.Value = Dir$(strImagePath)
          DoCmd.GoToControl "sbfrmProductImages"
    Else
          DoCmd.GoToControl "sbfrmProductImages"
         DoCmd.GoToRecord , , acNewRec
        Me!ProductImageLocalPath = strImagePath
       Me!ProductImageFileNm.Value = Dir$(strImagePath)
    End If
    
End Function

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I need someway of a GotFocus Event Code on the subform sbfrmProductImages to repopulate the Image126 Controller on the Main form when I click on the record row.

Thank you!
0
Dustin Stanley
Asked:
Dustin Stanley
  • 4
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2 Solutions
 
hnasrCommented:
It is hard to understand the problem from just VBA code.
If you can reproduce the issue in a single database, upload to check. Explain the required output.
0
 
Dustin StanleyEntrepreneurAuthor Commented:
db105.jpg
In the photo I have attached there is a image control on the mainform with a school bus in it. This image control is called "Image126".

Image126 knows which picture to display because of the VBA code:

Call SetFormAllowAdditions(Me!sbfrmProducts.Form, 4)
    
    On Error GoTo ExitProc
    Dim ImagePath As String
    
   
    ImagePath = GetProductImageFilePath & Forms!frmSkusEntry!sbfrmProductImages.Form!ProductImageFileNm

    If Len(Forms!frmSkusEntry!sbfrmProductImages.Form!ProductImageFileNm) > 0 And Len(Dir(ImagePath)) > 0 Then
        Image126.Picture = ImagePath
    Else
        Image126.Picture = ""
    End If
    
ExitProc:
    Exit Sub
ErrProc:
    Select Case Err.Number
        Case Else
            Resume ExitProc
    End Select
End Sub

Public Function GetProductImageFilePath() As String
    GetProductImageFilePath = GetDBPath & "images\"
End Function


    Public Function GetDBPath() As String
    GetDBPath = Replace(CurrentDb.TableDefs("Assemblies").Connect, ";DATABASE=", "")
'Remove db name
GetDBPath = Left(GetDBPath, InStrRev(GetDBPath, "\"))

End Function

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I place the information into the table called "ProductImages" which has fields "ProductImageFileNm" and "ProductImageLocalPath" in the subform "sbfrmProductImages" with the Add Image Button next to Image126 in the mainform using code:

Public Function AddLocalImagePath() As Variant
Dim strImagePath As String

    strImagePath = GetFile_Browse
    
    If Me.NewRecord Then
        Me!ProductImageLocalPath = strImagePath
         Me!ProductImageFileNm.Value = Dir$(strImagePath)
          DoCmd.GoToControl "sbfrmProductImages"
    Else
          DoCmd.GoToControl "sbfrmProductImages"
         DoCmd.GoToRecord , , acNewRec
        Me!ProductImageLocalPath = strImagePath
       Me!ProductImageFileNm.Value = Dir$(strImagePath)
    End If
    
End Function

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ProductImageFileNm = File Name Only

ProductImageLocalPath = Full Path to the file (***PLEASE IGNORE THIS FIELD AS IT IS NOT THE TRUE PATH. JUST THE PATH FROM THE USER TO THE FILE THEY CHOSE***)

In the Main Larger Code it finds the database backend path and concatenates the database backend path and ProductImageFileNm together to create the true full path for Image126 to display.

Now when I add multiple images which is multiple rows (Records) the photo in Image126 doesn't change when I click on the next record in the subform sbfrmProductImages.

Somewhere somehow something has to requery or refresh (Not sure which one) for Image126 to change the image to what current record I am focused on.

I hope that helps and thank you for time.
0
 
Dustin StanleyEntrepreneurAuthor Commented:
Ok I got it!

I had to place this in my sbfrmProductImages ONCURRENT event:

Private Sub Form_Current()
       
    On Error GoTo ErrProc
    Dim ImagePath As String
    
  
    ImagePath = GetProductImageFilePath & Forms!frmSkusEntry!sbfrmProductImages.Form!ProductImageFileNm
    
    If Len(Forms!frmSkusEntry!sbfrmProductImages.Form!ProductImageFileNm) > 0 And Len(Dir(ImagePath)) > 0 Then
        Forms!frmSkusEntry!Image126.Picture = ImagePath
    Else
        Forms!frmSkusEntry!Image126.Picture = ""
    End If
    
ExitProc:
    Exit Sub
ErrProc:
 MsgBox "ERROR"
    Select Case Err.Number
        Case Else
            Resume ExitProc
    End Select
End Sub

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hnasrCommented:
Dustin Stanley
It is a relief when you figure out your solution to the problem.
It will be highly appreciated, by future visitors of this question,  if you add a short comment summarizing the solution..
0
 
Dustin StanleyEntrepreneurAuthor Commented:
summarizing the solution

I had to place the same code from my mainform oncurrent event into my subforms oncurrent event when multiple product images were available in my subform and used with a single main form Image Control.
0
 
hnasrCommented:
Thank you.
0
 
Dustin StanleyEntrepreneurAuthor Commented:
I received no response but from one person who wanted me to upload a DB because it was hard to understand the problem but at least someone responded. I then figured it out on my own! Thank you hnasr!
0

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