Get Javascript URL parameters

I am using jPList - jQuery Data Grid Controls - http://jplist.com

and I am using the deep linking feature: http://jplist.com/documentation/deep-links

which creates an URL parameter on filter change.

I am getting a parameter like the below...

http://www.domain.com/hardware/printers//hardware/printers/#sort:path~type~order=.title~text~asc|category-checkbox-dropdown:pathGroup=.vutek_mid_range~.vutek_high_volume|range-slider-print-width:prev~next=0~3200

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Can you please tell me how I would get the relevant parameter to use within the page?

For example I would like to say...

If  "category-checkbox-dropdown:pathGroup" includes ".vutek_mid_range" return "Yes"?

I would prefer to use php for this, but if not Jquery is fine.
petewinterAsked:
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Julian HansenConnect With a Mentor Commented:
Just had a look at your URL again - the data you want is in the hashtag which is not sent to the server so you don't have a PHP option

JavaScript
<script>
function checkFor(key, value)
{
  var parts = window.location.hash.substr(1).split('|');
  for(var i in parts) {
    if (parts[i].indexOf(key) != -1) {
      if (parts[i].indexOf(value) != -1) {
        return true;
      }
    }
  }
  return false;
}
if (checkFor('category-checkbox-dropdown:pathGroup', '.vutek_mid_range')) {
  alert('yes');
}
else {
  alert('no');
}
</script>

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Julian HansenCommented:
I would prefer to use php for this, but if not Jquery is fine.
PHP is server side, jQuery is client side - they are not interchangeable

Where do you want to use this information?  

Please describe a use case.
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petewinterAuthor Commented:
Hi Julian

Thanks for the reply and sorry for the confusion.

I will be linking to this parameter from another page. So when the page loads I only want to show a particular block of code if the parameter exists.

So if I was using php I would generally use code like the below...

if ( $_GET['parameter'] == "xxx") { .... }

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And something similar for jQuery.

Hope that makes sense?
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petewinterAuthor Commented:
Perfect. Many thanks
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Julian HansenCommented:
You are welcome.
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Ray PaseurCommented:
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petewinterAuthor Commented:
Many thanks Ray
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