find out if a cell has yellow fill

i need a formula to test if a cell has been filled with yellow.

any ideas?
finnstoneAsked:
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frankhelkConnect With a Mentor Commented:
P.S.: To provide more amusement to the crowd, here's the luxury version of the function, which allows to check for any desired color:

Public Function IsCellColor(r As Range, Red As Integer, Green As Integer, Blue As Integer) As Variant

    If r.Cells.Count > 1 Then
        IsCellYellow = CVErr(xlErrRef)
        Exit Function
    End If
    
    If (Red < 0) Or (Red > 255) _
        Or (Green < 0) Or (Green > 255) _
        Or (Blue < 0) Or (Blue > 255) Then
        IsCellYellow = CVErr(xlErrValue)
        Exit Function
    End If
            
    IsCellYellow = r.Interior.Color = RGB(255, 255, 0)

End Function

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Should be mostly self-explaining ...  ;-)
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Martin LissOlder than dirtCommented:
In the Immediate window of Visual Basic, type

?Range("A1").interior.color ' Change A1to the address of a yellow cell

That will return a 6 to 8 digit number and you can use that number when looking at other cells.
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frankhelkCommented:
The tip to the Range().Interior.Color property is basically correct, here's just some clarification:

The returned value is the value returned by the RGB()  function for the respective color, and it consists of the values for Red, Green and Blue in that color. The help for RGB() shows some examples for that, and "classic" Yellow is defined as RGB(255,255,0) or 65535.

Internal it's represented as a 3 Byte integer value, where the right byte (the least significant) represents red, the middle one represents green, and the right one (the most significant) represents blue.

RGB(255,0,0) = 255 = Red
RGB(0,255,0) = 65280 = Green
RGB(0,0,255) = 16711680 = Blue
RGB(0,0,0) = 0 = Black
RGB(255,255,255) = White = 16777215

With that in mind, the minimum length of that number is 1 (for values ranging from 0 (Black) to 8 (an almost invisible faint red).

To check for a yellow cell, the statement would be
if Range(address).Interior.Color = RGB(255,255,0) then (...)

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Rob HensonFinance AnalystCommented:
As far as I know it is not possible in standard formulas. You could possibly use a User Defined Function (UDF) which is basically a Visual Basic script that is triggered in the same way as a formula.

Alternatively, looking at it differently, is there a quantifiable reason why a cell would be coloured yellow?
Could that reason for the colour be converted to a Conditional Format so that a cell will automatically go yellow when a condition is met? If that were the case, you could then test for the condition that triggers the format rather than testing for the format itself.

Thanks
Rob H
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finnstoneAuthor Commented:
what can i type in excel to make any of these work?
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frankhelkCommented:
The most easy way is a user defined function. Open the VBA editor, insert a new module and paste the following code into:

Public Function IsCellYellow(r As Range) As Variant

    If r.Cells.Count > 1 Then
        IsCellYellow = CVErr(xlErrRef)
        Exit Function
    End If
        
    IsCellYellow = r.Interior.Color = RGB(255, 255, 0)

End Function

Open in new window


Use as explained in the attached example workbook.

The function allows a reference to exactly 1 cell and checks if the background is yellow. The result is returned as boolean (true/false). If more than 1 cell is referenced, an Excel error is returned. The function could be used at any place where a boolean value is allowed (i. e. IF(), IIF(), .... )

Hope that helps.
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finnstoneAuthor Commented:
thank you!
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frankhelkCommented:
Oops - mea maxima culpa ... I've made a quick shot and produced an error ... it takes arguments but still checks for yellow. The function should read

Public Function IsCellColor(r As Range, Red As Integer, Green As Integer, Blue As Integer) As Variant

    If r.Cells.Count > 1 Then
        IsCellYellow = CVErr(xlErrRef)
        Exit Function
    End If
    
    If (Red < 0) Or (Red > 255) _
        Or (Green < 0) Or (Green > 255) _
        Or (Blue < 0) Or (Blue > 255) Then
        IsCellYellow = CVErr(xlErrValue)
        Exit Function
    End If
            
    IsCellYellow = r.Interior.Color = RGB(Red, Green, Blue)

End Function

Open in new window


( Just 1 line changed, the final test ...)

And here's the promised example workbook, too: Example.xlsm
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