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Search for strings with a white space in sql

Posted on 2016-11-02
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Last Modified: 2016-11-02
Hello,

I have a stored procedure to search a string but, it fails when it has white spaces at the beginning of it.
Example: 'abc'  searches perfectly but, ' abc' fails. Cannot use like in the query.
The query I have is
  SET @SQL = @SQL + '  AND Auth = ''' +  CAST(@Auth AS NVARCHAR(50))+ ''''	 

Open in new window


Regards
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Question by:RIAS
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9 Comments
 
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Expert Comment

by:Trideep Patel
ID: 41869882
What is the value in your database table is it 'abc' or ' abc' with blank?
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Accepted Solution

by:
Vitor Montalvão earned 500 total points
ID: 41869883
Use LTRIM to remove the spaces from the beginning of the string. You can also use RTRIM if you want to remove the spaces at the end of the string. So, the following will remove spaces from begin and end of the string:
SET @SQL = @SQL + '  AND Auth = ''' +  LTRIM(RTRIM(CAST(@Auth AS NVARCHAR(50)))) + ''''	 

Open in new window

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Author Closing Comment

by:RIAS
ID: 41869900
Great Solution as always! Cheers!
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Author Comment

by:RIAS
ID: 41869919
Vitor,
Sorry for the confusion.
The data in the table is with space  example ' abc'
So need to search that.  Your solution trims the string for search but the data is with space

Cheers
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Expert Comment

by:Vitor Montalvão
ID: 41869926
Do you mean when @Auth = ' abc' (with leading space) your original query doesn't work?
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Author Comment

by:RIAS
ID: 41869932
The data in the table is ' abc'.
my original query was
SET @SQL = @SQL + '  AND Auth = ''' +  CAST(@Auth AS NVARCHAR(50))+ ''''	 

Open in new window


was not able to give result.
It is just one of them as cannot change data in table.
Can I  have a query which searches even the ones with leading spaces
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LVL 50

Expert Comment

by:Vitor Montalvão
ID: 41869952
Ok. It's the data in the table that has the space and not the variable. So use my above solution but on the column name. Mind that this can reduce the query performance if Auth is indexed:
SET @SQL = @SQL + '  AND LTRIM(RTRIM(Auth)) = ''' +  CAST(@Auth AS NVARCHAR(50))+ ''''	 

Open in new window

1
 

Author Comment

by:RIAS
ID: 41869957
Thanks will try and be right back
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Author Comment

by:RIAS
ID: 41869968
Worked like charm! Thanks
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