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Excel VBA - Highlight specific characters in a string

Posted on 2016-11-05
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62 Views
Last Modified: 2016-11-17
I have this in a cell formatted Wingdings2 (example)
Activecell.Value = Chr(188) & Chr(189) & Chr(154) & Chr(152)

Edit: It goes that as a UDF (   =GetAttenanceString("C10") for example  )
It works OK when the string is actually entered in the cell. Mystery!


Where the character is Chr(154) I want to color it Red. I'm doing it like this. BUT, although the If condition seems to work the entire string is being colored Red, rather than just the Chr(154). What am I missing here please?

Sub BlankNonAttendingDays()

    For iDay = 1 To 7
        If Mid(ActiveCell.Value, iDay, 1) = Chr(154) Then
            'MsgBox iDay
        
            With ActiveCell.Characters(Start:=iDay, Length:=1).Font
                .Size = 11
                .Color = 192
            End With
        End If

    Next iDay

End Sub

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Question by:hindersaliva
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5 Comments
 
LVL 18

Assisted Solution

by:Roy_Cox
Roy_Cox earned 250 total points
ID: 41875338
Why are using ActiveCell? An example workbook would help
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Author Comment

by:hindersaliva
ID: 41875345
ActiveCell for testing Roy. Yes I'll post a workbook later today.
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LVL 30

Expert Comment

by:Subodh Tiwari (Neeraj)
ID: 41875365
You cannot format the part of the text returned by the formula.
Copy and paste the value in another cell and the same piece of code would work without an issue with the cell with value only.
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LVL 30

Accepted Solution

by:
Subodh Tiwari (Neeraj) earned 250 total points
ID: 41875368
Or you should try something like this.....
Sub BlankNonAttendingDays()
ActiveCell.Value = ActiveCell.Value 'This line will remove the formula and place the value
    For iDay = 1 To 7
        If Mid(ActiveCell.Value, iDay, 1) = Chr(154) Then
            With ActiveCell.Characters(Start:=iDay, Length:=1).Font
                .Size = 11
                .Color = 192
            End With
        End If
    Next iDay
End Sub

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LVL 18

Expert Comment

by:Roy_Cox
ID: 41892506
Pleased to help
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