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How to count days per month between two dates using an Access function

Posted on 2016-11-08
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Last Modified: 2016-11-11
Hi everyone,

Can someone help me choose the right function to count the number of days per month within a given set of dates?

A small sample file attached.

I can get the the total count of days between the two days, using this:
Total Days: ((((DateDiff("d",[StartDate],[EndDate]))+1)/7)*[DaysPerWeek]*[HoursPerDay])/8
but what I need is the total count of days for each month between the dates.

Optimally, I need to show something like this (summing the total days in each month for all Orders whose dates fall within those months):
Month     Total Days
Sep               90.23
Oct                125.15
Nov               150.85
Book1.xlsx
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Question by:fabi2004
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23 Comments
 
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by:COACHMAN99
Comment Utility
is it always all days in the month, or sometimes part month?
and will your dates span years?
and what about leap years?
use the code on this link.
http://www.iaccessworld.com/wp-content/uploads/2016/06/function.png
or
http://www.projectperfect.com.au/microsoft-access-sample-6.htm
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by:fabi2004
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The formula has to take into account the number of days per week as well as the hours per day, then divide the whole thing by a regular 8 hour day to get the "work days".

So if Start Date is 10/24/2016, End Date 11/4/2016
Days per Week are 4
Hours per Day are 10

Then the result should be
Oct:
  (8 days/7 days in a week) = work weeks
   Work Weeks * 4 Days per week * 10 hours per day= Total hours worked
  Total hours worked / 8 hour day = Total Work Days (based on an 8 hour day)
= 5.71 days
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by:COACHMAN99
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in response to your question 'Can someone help me choose the right function to count the number of days per month within a given set of dates', the functions provided (above) will do,
24/10/2016 to 4/11/2016 is 9 working days and 11 in total - neither have 4 days/week?
I believe I have answered your original question but do not have time to address the second - hopefully someone else will run with this.
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by:fabi2004
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I may not have expressed my question correctly.  It is not necessarily the total days in month I need.  It is the total number of days between two sets of dates subtotaled by month.

For example, if the dates are 10/14/16 through 12/05/16, then I need to know how many of the total days fall in October, how many fall in November and how many fall in December.

There there's the additional calculation of days/week and hours/day, but I think I can add that in easily if I knew how to subtotal my days by month.

I found a custom SQL function by WayneS on the Internet:  http://www.sqlservercentral.com/Forums/Topic1022335-149-1.aspx
But I don't know how to modify this to work in Access.
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by:yo_bee
Comment Utility
are Sat and Sun included?
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by:hnasr
Comment Utility
two dates using an Access function

Open in new window

Upload sample data in an access database.
Add few representative records, and show the required output.
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by:COACHMAN99
Comment Utility
Run a while same-month loop, inside a while not last date loop, incrementing an integer array (of 12 months)  cell at the same time as incrementing the compare date toward the end-of-range date. Each time you reach the end of a month you should increment the array cell index.
The end result will be a number of cells containing the number of days in each month.
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by:Gustav Brock
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This query will return your list of days count:
PARAMETERS 
    DateStart DateTime, 
    DateEnd DateTime;
SELECT DISTINCT 
    10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10) AS Factor, 
    Year(DateAdd("m",[Factor],[DateStart])) AS [Year], 
    Month(DateAdd("m",[Factor],[DateStart])) AS [Month], 
        IIf(DateDiff("m",DateAdd("m",[Factor],[DateStart]),[DateEnd])=0,
            Day([DateEnd]),Day(DateSerial(Year(DateAdd("m",[Factor],[DateStart])),Month(DateAdd("m",[Factor],[DateStart]))+1,0))
                -IIf([Factor]=0,Day([DateStart])-1,0)) AS Days
FROM 
    msysobjects AS Uno, 
    msysobjects AS Deca
WHERE 
    (((10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10))<=DateDiff("m",[DateStart],[DateEnd])));

Open in new window


Example from 2015-12-15 to 2016-04-17:
Sample output/gustav
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by:fabi2004
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Gutav, your coding is so far above my skill level that I don't even know how to use it.  Do you happen to have enough patience to walk me through how to implement it in my db?
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by:fabi2004
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Gustav your code is flawless.  Now I "think" all I need is to find out how to pass a table field into the parameter.
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by:Gustav Brock
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That is quite simple to do. If your table is named Dates, then:
SELECT DISTINCT 
    Dates.Id, 
    Dates.DateStart, 
    Dates.DateEnd, 
    10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10) AS Factor, 
    Year(DateAdd("m",[Factor],[DateStart])) AS [Year], 
    Month(DateAdd("m",[Factor],[DateStart])) AS [Month], 
        IIf(DateDiff("m",DateAdd("m",[Factor],[DateStart]),[DateEnd])=0,
            DateDiff("d",[DateStart],[DateEnd]),Day(DateSerial(Year(DateAdd("m",[Factor],[DateStart])),Month(DateAdd("m",[Factor],[DateStart]))+1,0))
                -IIf([Factor]=0,Day([DateStart])-1,0)) AS Days
FROM 
    msysobjects AS Uno, 
    msysobjects AS Deca,
    Dates
WHERE 
    (((10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10))<=DateDiff("m",[DateStart],[DateEnd])));

Open in new window

Note please, that I've corrected an error in the day count of the first month in those cases where both dates fall in the same month, and in the day count of the last month which was off by 1.

Example:
Sample/gustav
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by:fabi2004
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I tried so many variations and none of them worked.  Thank you for clarifying that for me.  It works great now except for the last month of the date span.  I seem to be getting strange results.

Sample Results
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by:Gustav Brock
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Sorry, introduced an error.
Here is the corrected query. I've added a field for the total count of days as a control:
SELECT DISTINCT 
    Dates.Id, 
    Dates.DateStart, 
    Dates.DateEnd, 
    10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10) AS Factor, 
    Year(DateAdd("m",[Factor],[DateStart])) AS [Year], 
    Month(DateAdd("m",[Factor],[DateStart])) AS [Month], 
        IIf(DateDiff("m",[DateStart],[DateEnd])=0,
            DateDiff("d",[DateStart],[DateEnd]),
            IIf(DateDiff("m",DateAdd("m",[Factor],[DateStart]),[DateEnd])=0,
                Day([DateEnd])-1,
                Day(DateSerial(Year(DateAdd("m",[Factor],[DateStart])),Month(DateAdd("m",[Factor],[DateStart]))+1,0))
                    -IIf([Factor]=0,Day([DateStart])-1,0))) AS 
    Days, 
    DateDiff("d",[DateStart],[DateEnd]) AS DaysTotal
FROM 
    msysobjects AS Uno, 
    msysobjects AS Deca, 
    Dates
WHERE 
    10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)<=DateDiff("m",[DateStart],[DateEnd]);

Open in new window

/gustav
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by:fabi2004
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Hi Gustav,

Thank you for sticking with me and helping with this.

It seems that Total Days and the day count of the last month may be off by 1.

I can easily modify the total days formula, ((DateDiff("d",[StartDate],[EndDate]))+1)

But I honestly don't know how to change your other formulas to add a day to the count of the last month.

Sample1
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Expert Comment

by:Gustav Brock
Comment Utility
No, the counts are not off by one. That's why I included the total column as control.
The count is 0 if DateStart equals DateEnd. If you wish to raise the count to include the end date, just add 1, but then you will never be able to have a count of zero.

/gustav
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by:fabi2004
Comment Utility
Correct, there should never be a count of zero.  StartDate 11/10/16  to EndDate 11/10/16 should be a count of 1 day.  I don't know how to fix that in your formulas because all but the last month of the count come out correctly.  How do I adjust just the last month of the date range's total?  The total column is off by one but that is an easy fix.
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Accepted Solution

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Gustav Brock earned 500 total points
Comment Utility
To cover all scenarios, you will to raise the end date by one; so either update the enddate, create an interim query where you add one day to the enddate and use this as source for the query, or add one day in the query itself:
SELECT DISTINCT 
    Dates.Id, 
    Dates.DateStart, 
    Dates.DateEnd,
    DateAdd("d",1,Dates.[DateEnd]) As DateEndNext, 
    10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10) AS Factor, 
    Year(DateAdd("m",[Factor],[DateStart])) AS [Year], 
    Month(DateAdd("m",[Factor],[DateStart])) AS [Month], 
        IIf(DateDiff("m",[DateStart],DateAdd("d",1,[DateEnd]))=0,
            DateDiff("d",[DateStart],DateAdd("d",1,[DateEnd])),
            IIf(DateDiff("m",DateAdd("m",[Factor],[DateStart]),DateAdd("d",1,[DateEnd]))=0,
                Day(DateAdd("d",1,[DateEnd]))-1,
                Day(DateSerial(Year(DateAdd("m",[Factor],[DateStart])),Month(DateAdd("m",[Factor],[DateStart]))+1,0))
                    -IIf([Factor]=0,Day([DateStart])-1,0))) AS 
    Days, 
    DateDiff("d",[DateStart],DateAdd("d",1,[DateEnd])) AS DaysTotal
FROM 
    msysobjects AS Uno, 
    msysobjects AS Deca, 
    Dates
WHERE 
    10*Abs([Deca].[id] Mod 10)+Abs([Uno].[id] Mod 10)<=DateDiff("m",[DateStart],DateAdd("d",1,[DateEnd]));

Open in new window

/gustav
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Expert Comment

by:yo_bee
Comment Utility
@gus

You should be paid for this help!    ;)
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by:Gustav Brock
Comment Utility
Thanks! That's not the way it goes, but you can start by clicking a thumbs up.

/gustav
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by:yo_bee
Comment Utility
I know.
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Author Closing Comment

by:fabi2004
Comment Utility
Thank you so very much for all of your help.  You've gone above and beyond with your patience and sharing your knowledge.  It is very much appreciated.
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by:fabi2004
Comment Utility
@yo_bee

Thanks man :-(  It wasn't like I wasn't feeling bad enough already.
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by:Gustav Brock
Comment Utility
Thank you. You are welcome!

/gustav
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