Solved

sql server query?

Posted on 2016-11-15
6
48 Views
Last Modified: 2016-11-16
Why am I not picking up '2016-10-29' in this query


Declare @StartDt date
Declare @EndDt date
Set @StartDt  = '2016-10-08'


--print @StartDt

Set @EndDt = '2016-11-02'

WHILE @StartDt <= @EndDt
BEGIN

SELECT
CONVERT(INTEGER, CONVERT(CHAR(10),  (DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt)))), 112)) AS YTDDateKey,
YEAR((DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt))))) AS [Year],
(DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt)))) as SatYTDDt, LoadDttm = getdate()



SET @StartDt = DATEADD(dd, 7, @StartDt)
END
0
Comment
Question by:elucero
6 Comments
 
LVL 51

Expert Comment

by:Ryan Chong
ID: 41888955
Why am I not picking up '2016-10-29' in this query
you are...

Declare @StartDt date
Declare @EndDt date
Set @StartDt  = '2016-10-08'
Set @EndDt = '2016-11-02'

WHILE @StartDt <= @EndDt
BEGIN

print @StartDt 

SET @StartDt = DATEADD(dd, 7, @StartDt)
END 

Open in new window


you are getting the output such as:
2016-10-08
2016-10-15
2016-10-22
2016-10-29

Open in new window


For the query:
SELECT
CONVERT(INTEGER, CONVERT(CHAR(10),  (DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt)))), 112)) AS YTDDateKey,
YEAR((DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt))))) AS [Year],
(DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt)))) as SatYTDDt, LoadDttm = getdate()

Open in new window

can you tell us what you intend to get here?
0
 
LVL 65

Expert Comment

by:Jim Horn
ID: 41888957
When I run your code on my SQL 2012 box @startdt='2016-10-08' is the first @startdt processed, but YTDDateKey=20161001.  

It would probably help if you could add some details as to what you're trying to accomplish here.
20161008.png
0
 
LVL 28

Accepted Solution

by:
Pawan Kumar earned 500 total points
ID: 41889005
try..Can you tell me the purpose of (DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt)))) as SatYTDDt

I have modified all your columns. Now it is picking  '2016-10-29'  

Other than this I think you need below.. please check?

Declare @StartDt date 
Declare @EndDt date
Set @StartDt  = '2016-10-08'
Set @EndDt = '2016-11-02'

WHILE @StartDt <= @EndDt 
BEGIN

PRINT @StartDt

SELECT
CONCAT(YEAR(@StartDt), RIGHT(CONCAT('0', MONTH(@StartDt)),2), RIGHT(CONCAT('0', DAY(@StartDt)),2))AS YTDDateKey,
CAST(@StartDt AS DATETIME) AS [Year],
(DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt)))) as SatYTDDt
, LoadDttm = getdate()

SET @StartDt = DATEADD(dd, 7, @StartDt)

END

Open in new window


Output


2016-10-08
YTDDateKey       Year                    SatYTDDt                LoadDttm
---------------- ----------------------- ----------------------- -----------------------
20161008         2016-10-08 00:00:00.000 2016-10-01 00:00:00.000 2016-11-16 07:59:01.773

(1 row(s) affected)

2016-10-15
YTDDateKey       Year                    SatYTDDt                LoadDttm
---------------- ----------------------- ----------------------- -----------------------
20161015         2016-10-15 00:00:00.000 2016-10-08 00:00:00.000 2016-11-16 07:59:01.773

(1 row(s) affected)

2016-10-22
YTDDateKey       Year                    SatYTDDt                LoadDttm
---------------- ----------------------- ----------------------- -----------------------
20161022         2016-10-22 00:00:00.000 2016-10-15 00:00:00.000 2016-11-16 07:59:01.773

(1 row(s) affected)

2016-10-29
YTDDateKey       Year                    SatYTDDt                LoadDttm
---------------- ----------------------- ----------------------- -----------------------
20161029         2016-10-29 00:00:00.000 2016-10-22 00:00:00.000 2016-11-16 07:59:01.773

(1 row(s) affected)
0
How Do You Stack Up Against Your Peers?

With today’s modern enterprise so dependent on digital infrastructures, the impact of major incidents has increased dramatically. Grab the report now to gain insight into how your organization ranks against your peers and learn best-in-class strategies to resolve incidents.

 
LVL 10

Expert Comment

by:HuaMinChen
ID: 41889195
Try
Declare @StartDt date 
Declare @EndDt date
Set @StartDt  = '2016-10-01'


--print @StartDt

Set @EndDt = '2016-11-02'

WHILE @StartDt <= @EndDt 
BEGIN
SET @StartDt = DATEADD(dd, 7, @StartDt)

SELECT
CONVERT(INTEGER, CONVERT(CHAR(10),  (DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt)))), 112)) AS YTDDateKey,
YEAR((DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt))))) AS [Year],
(DATEADD(wk, 0, DATEADD(DAY, 0-DATEPART(WEEKDAY, @StartDt), DATEDIFF(dd, 0, @StartDt)))) as SatYTDDt, LoadDttm = getdate()



END

Open in new window

0
 
LVL 49

Expert Comment

by:Vitor Montalvão
ID: 41889294
Why am I not picking up '2016-10-29' in this query
Tell us what you want to do with the query.

What's actually doing is processing the last week based in the current day and that's why '2016-10-29' isn't returned. When '2016-10-29' it's processing '2016-10-22' (one week before).
0
 

Author Closing Comment

by:elucero
ID: 41890095
Thanks!
0

Featured Post

Online Training Solution

Drastically shorten your training time with WalkMe's advanced online training solution that Guides your trainees to action. Forget about retraining and skyrocket knowledge retention rates.

Question has a verified solution.

If you are experiencing a similar issue, please ask a related question

The Delta outage: 650 cancelled flights, more than 1200 delayed flights, thousands of frustrated customers, tens of millions of dollars in damages – plus untold reputational damage to one of the world’s most trusted airlines. All due to a catastroph…
In this article we will learn how to fix  “Cannot install SQL Server 2014 Service Pack 2: Unable to install windows installer msi file” error ?
Using examples as well as descriptions, and references to Books Online, show the documentation available for date manipulation functions and by using a select few of these functions, show how date based data can be manipulated with these functions.
Viewers will learn how to use the SELECT statement in SQL and will be exposed to the many uses the SELECT statement has.

733 members asked questions and received personalized solutions in the past 7 days.

Join the community of 500,000 technology professionals and ask your questions.

Join & Ask a Question