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Javascript: Find and Enable Submit Button in Table

I have a dynamically created table. Each row of the table includes form elements. It includes a drop down and a submit button.
The submit button is disabled by default and I want in enabled when I change the drop down.
The following function works great in making changes and calculation on the other data in the row, but I can't seem to get the SubmitButton to enable. Can someone tell me what I'm doing wrong?

// Chnages Op on rank change
	$(".rank").change(function() {
    var $rankop = this.value; // get Rank value
    var $catrow = $(this).closest("tr");    // Find the row
    var $catop1 = $catrow.find(".catop").text(); // Find cat Op
	var $baseop = $catrow.find(".baseop").val(); // Find baseop
	var $catop = ($rankop * $baseop); // Multiply ranking x op for new op 
	    $catop =$catop.toFixed(2);    // format to 2 decimal points
		
	$catrow.find(".rankop").val($rankop); // change value of hidden field calcop for form submit
	$catrow.find(".calcop").val($catop); // change value of hidden field calcop for form submit
	$catrow.find(".catop").text($catop); // change text of catop cell to new op
	$catrow.find(".SubmitButton").disabled = false; // Enable Submit Button. This is part that does not work

});	

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dannyg280
Asked:
dannyg280
  • 2
1 Solution
 
Julian HansenCommented:
If youre table is dynamic - do you mean in the browser or in how it is rendered on the server?

You may be running into the problem of binding to the row before it is created. Try changing this (Line 2)
$(".rank").change(function() {

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To this
$('body').on('change', '.rank', function() {

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With the above change - even if you add rows to the table in the browser the change event will fire.
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Julian HansenCommented:
Also change your line 13 to this

$catrow.find(".SubmitButton").prop({disabled: false});

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Use the prop() method
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dannyg280Author Commented:
Perfect. Thank you
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