Check which ports are open to the outside world. Helps make sure that your firewall rules are working as intended.
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yields some indecipherable second element of each tuple. What I want to get back from that is:
import itertools as itr In : list(itr.groupby('1222311')) Out: [('1', <itertools._grouper at 0x3cae048>), ('2', <itertools._grouper at 0x3cae630>), ('3', <itertools._grouper at 0x3caedd8>), ('1', <itertools._grouper at 0x3cae1d0>)]
though the order of elements within the tuples is irrelevant.
[('1', 1), ('2', 3), ('3', 1), ('1', 2)]
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