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Microsoft Lync 2013

Posted on 2016-11-18
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Last Modified: 2016-11-22
Hi,

I have 2 VM servers set as front end pool servers and they are not clustered at the moment. If I create a 2 node MS failover cluster on VMware 6.0  and use same disks  would that cause any issues?

I can be wrong but my concern is that as disks are in use, will I have inconsistent data in cluster? do I need to delete the disk and start from fresh?

current VM disks are set in virtual mode and eager zero thick type.

tanks
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Question by:kuzum
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Andrew Hancock (VMware vExpert / EE MVE) earned 500 total points
ID: 41892692
How are you going to create a two node cluster using VMDKs ?

it's only supported for Cluster in a Box, which is used for demonstration purposes, not really supported for a Microsoft Failover Cluster, iSCSI RDM or Fibre Channel RDM are used for Failover Clustering.

You will need to start from scratch to build your cluster disks (VMDKS) if you want to use Cluster in a Box.

Microsoft Clustering on VMware vSphere: Guidelines for supported configurations (1037959)

Setup for Failover Clustering and Microsoft Cluster Service ESXi 6.0 vCenter Server 6.0
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by:kuzum
ID: 41892706
Hi Andrew

I think we are on the same page. my findings are from this page and yes it has to be cluster in Box and yes it will be VMDKs, disk size are 400GB so I believe disk do  not have to be RDM but it still has to be in physical mode?

https://pubs.vmware.com/vsphere-60/topic/com.vmware.ICbase/PDF/vsphere-esxi-vcenter-server-60-setup-mscs.pdf

So question is:   DO I need to build everything from scratch using physical mode or virtual mode?
and I need to restore all SQL databases for lync  to new design so it can be up to date again?
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LVL 118
ID: 41892734
I would NOT recommend Cluster in a Box approach, again, it's used for Demonstrations, not designed for Production.

You will need to use Virtual SCSI Bus Sharing, it' easier to setup new, than trying to re-engineer

http://wojcieh.net/microsoft-cluster-running-on-vmware-esxi-cluster-in-a-box/
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Author Closing Comment

by:kuzum
ID: 41897303
as it sounded in the official docs. NOT worth wasting time on this
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