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  • Status: Solved
  • Priority: Medium
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  • Last Modified:

How to order Highest and lowest value rows alternatively in SQL Server ?

Sample data-

CREATE TABLE #emp_records
(
 Id INT,
 Name VARCHAR(80),
 Salary NUMERIC(8, 2)
)
GO
 
INSERT INTO #emp_records
(Id, Name, Salary)
VALUES(1, 'A', 7000),
(2, 'B', 30000),
(3, 'C', 6000),
(4, 'D', 10000),
(5, 'E', 800),
(6, 'F', 500)

Desired Output :-

Id      Name      Salary
2      B      30000.00
6      F      500.00
4      D      10000.00
5      E      800.00
1      A      7000.00
3      C      6000.00
0
Mayank Tripathi
Asked:
Mayank Tripathi
  • 2
  • 2
1 Solution
 
Pawan KumarDatabase ExpertCommented:
Do you always have even number in this case ? or we can have odd number also ?
0
 
Mayank TripathiAuthor Commented:
Thanks Pawan, by the way the rows are not fixed.
0
 
Pawan KumarDatabase ExpertCommented:
try..

---

DECLARE @Count INT = 0
SELECT @Count = COUNT(1) FROM emp_records
DECLARE @limit INT = CEILING(@Count / 2.0)

;WITH CTE AS
(
	SELECT * FROM
	(
		SELECT * , ROW_NUMBER() OVER(ORDER BY Salary DESC) rnk FROM emp_records
	)B1 
	WHERE rnk <= @limit
)
,CTE1 AS 
(
	SELECT * FROM
	(
		SELECT *, ROW_NUMBER() OVER(ORDER BY Salary ASC) rnk FROM emp_records
	)B2
	WHERE rnk <= @limit - (@Count % 2.0) 
)
SELECT * FROM CTE c
UNION ALL
SELECT * FROM CTE1
ORDER BY rnk ASC, Salary DESC

Open in new window


Hope it helps !
0
 
Mayank TripathiAuthor Commented:
Thanks.
0

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