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Powershell question about a text file

Posted on 2016-11-23
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Last Modified: 2016-11-23
I have a text file with

Verkoper: JEAN-PAUL Leverdatum 7-11-2016
Nr. Omschrijving Aantal Stukprijs Verp.bel Bedr.incl.verp.
21051 Coca Cola Krat 24x20 cl 70 7,80 546,00
60547 Emballage Euro 5,00 70 5,00 350,00
22005 Coca Cola Light Krat 24x20 cl 10 8,20 82,00
60547 Emballage Euro 5,00 10 5,00 50,00

Wat is the best way to get only the last numbers and to add up so i need 546+350+82+50=1028

Thanks Danny
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Question by:Danny Kon
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Accepted Solution

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oBdA earned 2000 total points
ID: 41899420
With a regular expression, for example:
$Amount = 0
Get-Content C:\Temp\Verkoper.txt | Where-Object {$_ -match '\s(?<Amount>\d+,\d\d)\s*\Z'} | ForEach-Object {$Amount += $Matches['Amount'].Replace(',', '.')}
$Amount

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Author Comment

by:Danny Kon
ID: 41899440
I am happy i finally can help you learning some dutch now :)
I can not give you bonus points but can you maybe explain how this work

Thanks Danny
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LVL 6

Author Comment

by:Danny Kon
ID: 41899452
oBdA

Because i think the question is to big i try to split the question in parts  but if you have maybe the time could you look at question

https://www.experts-exchange.com/questions/28984972/Powershell-to-extract-the-important-data-and-calculate-if-the-amounts-are-correct.html

Thanks again Danny
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LVL 86

Expert Comment

by:oBdA
ID: 41899463
'\s(?<Amount>\d+,\d\d)\s*\Z' checks if the line matches
\s - a space, followed by
\d+ - at least one digit (more OK), followed by
, - a comma, followed by
\d\d - exactly two digits, followed by
\s* - any number of spaces (zero OK), followed by
\Z - end of string.
The (<Amount>...) is a named capturing group that captures the amount in question, without the unnecessary stuff around it.
If a match is found, the $Matches variable will contain a key 'Amount' with the captured content.
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Author Closing Comment

by:Danny Kon
ID: 41899693
Perfect answer and quick respons
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Author Comment

by:Danny Kon
ID: 41899714
But how the command knows you want the last number
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LVL 86

Expert Comment

by:oBdA
ID: 41899719
Because the "\Z" at the end "anchors" the expression to the string's end.
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LVL 6

Author Comment

by:Danny Kon
ID: 41899726
Last question and if i wanted the 70, 70, 10, 10 third number from the right
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LVL 86

Expert Comment

by:oBdA
ID: 41899754
Yes, I'll have a look at your other question ...
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LVL 6

Author Comment

by:Danny Kon
ID: 41899945
:)
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