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sql query

Posted on 2016-11-30
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Last Modified: 2016-11-30
In the attached table the column remark has the data as shown. I need to extract the part of the string after the alphabet "k" where "k" is included and in the third row it should return null as "k" is not there. Please help me with the query to fetch the data from this column. the table name is Table1.Table1
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Question by:sam shah
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9 Comments
 
LVL 29

Expert Comment

by:Pawan Kumar
ID: 41906962
Try..

SELECT * FROM
(
  select (CASE WHEN instr(remark,'k') > 0 THEN substr(remark,instr(remark,'k',-1)) ELSE NULL END) Extensions from YourTable
)
0
 
LVL 29

Expert Comment

by:Pawan Kumar
ID: 41906966
Testing..

WITH CTE AS
(
 
   SELECT 'ab12 k1234567' remark FROM DUAL UNION ALL
   SELECT 'cd13 k1234'  FROM DUAL UNION ALL
   SELECT 'ef14 1234'  FROM DUAL UNION ALL
   SELECT ''  FROM DUAL
)    
SELECT * FROM 
(
  select (CASE WHEN instr(remark,'k') > 0 THEN substr(remark,instr(remark,'k',-1)) ELSE NULL END) Extensions from CTE
)

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Output



 	EXTENSIONS
1	k1234567
2	k1234
3	NULL
4	NULL

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Hope it helps !!
0
 

Author Comment

by:sam shah
ID: 41906972
where is the table name in the above code and what is "WITH CTE AS" for? can you plz explain a bit.
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LVL 29

Accepted Solution

by:
Pawan Kumar earned 2000 total points
ID: 41906973
That I just use for the  testing purpose. Basically creating a table at runtime..

You can use below- <<Replace CTE with your tablename>>

SELECT * FROM 
(
  select (CASE WHEN instr(remark,'k') > 0 THEN substr(remark,instr(remark,'k',-1)) ELSE NULL END) Extensions from CTE
)

Open in new window

0
 

Author Closing Comment

by:sam shah
ID: 41906978
Thanks a lot.
0
 
LVL 38

Expert Comment

by:Geert Gruwez
ID: 41907017
regexp is also a good choice ...

if you only want the numbers
with sample as (
  select 'ab12 k123567' x from dual
  union all select 'cd13 k1234' from dual
  union all select 'ef14 1234' from dual)
select regexp_substr(x, 'k(\d*)', 1, 1, 'i', 1) from sample

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if you want k and the numbers
with sample as (
  select 'ab12 k123567' x from dual
  union all select 'cd13 k1234' from dual
  union all select 'ef14 1234' from dual)
select regexp_substr(x, 'k(\d*)') from sample

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leaving a question open some time allows time for alternatives :)
0
 

Author Comment

by:sam shah
ID: 41907112
select remarks, regexp_substr(remarks,'\d+$') from table1;  

i used this but it is not returning the value along with "k". it is just returning the digits.
0
 
LVL 32

Expert Comment

by:awking00
ID: 41907277
Is it possible to have more than one 'k'?
0
 
LVL 38

Expert Comment

by:Geert Gruwez
ID: 41907323
\d > indicates a digit
+ indicates 1 or more 
$ indicates at the end of string

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http://www.regular-expressions.info/refquick.html

so you want the last digits ?
your regex doesn't include a k

the k with digits if in the end of the line :  

with sample as (
  select 'ab12 k123567' x from dual
  union all select 'cd13 k5678 k1234' from dual
  union all select 'ef14 1234' from dual)
select regexp_substr(x, 'k\d+$') from sample

Open in new window


if the k and digits are not at the end of the line, then the row is not found
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