by zero exception

>>I wonder where above message came from<<
What above message?

, and the message you get is the detail message for that exception

that is defined in API iteself by jdk?

when i ran my program i did not get detailed like below

Exception in thread "main" java.lang.ArithmeticException: / by zero
        at Exceptions.main(Exceptions.java:5)


but insteead i just got
/ by zero
please advise

I added some lines that hopefully explain.  

public class Exceptions {
	public static void main(String[] args) {
		try{
			int a = 5;
			int b = 0;
			int c = a/b;
		} catch(Exception e){
			System.out.println(" message is " + e.getMessage());
			System.out.println(" toString() is " + e.toString());
			System.out.println("--------------------------------------");
			e.printStackTrace();
		}
		
	}
}

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When I run that, I get

 message is / by zero
 toString() is java.lang.ArithmeticException: / by zero
--------------------------------------
java.lang.ArithmeticException: / by zero
        at Exceptions.main(Exceptions.java:6)

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I forgot to answer your question.

that is defined in API iteself by jdk?

Somewhere in the bowels of Java (hopefully an expert will tell us where) an ArithmeticException is constructed using the constructor
http://docs.oracle.com/javase/8/docs/api/java/lang/ArithmeticException.html#ArithmeticException-java.lang.String- 
I post it here.

public ArithmeticException(String s)
Constructs an ArithmeticException with the specified detail message.
Parameters:
s - the detail message.

So,  somewhere there is code like

throw new ArithmeticException("/ by zero");

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catch (Exception e) {
                  // TODO: handle exception
                  System.out.println(e.getMessage());

i just printed e.getMessage

not

e.printStackTrace();

which i usually used to do..

public class ExceptionsMessage {

	public void test() throws NullPointerException {
		NullPointerException e = new NullPointerException("");
		throw e;
	}

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		// int arr[] = { 1, 2, 3, 4, 5 };

		try {
			// System.out.println(arr[5]);
			//System.out.println("next");
			// } catch (NullPointerException e) {
			//Exceptions obj = new Exceptions();
			//obj.test();
			int a=5;
			int b=0;
			int c=a/b;

		}
		// System.out.println("in between try and catch");
		// catch (ArrayIndexOutOfBoundsException e) {
		// catch (NullPointerException e) {
		catch (Exception e) {
			// TODO: handle exception
			//System.out.println(e.getMessage());
			//System.out.println(e.printStackTrace());
			e.printStackTrace();
		}
		// System.out.println("hi");
	}

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above gave what i am looking output

java.lang.ArithmeticException: / by zero
      at com.mkyong.test.core.ExceptionsMessage.main(ExceptionsMessage.java:22)

public class ExceptionsMessage {

	public void test() throws NullPointerException {
		NullPointerException e = new NullPointerException("");
		throw e;
	}

	public static void main(String[] args) {
		// TODO Auto-generated method stub
		// int arr[] = { 1, 2, 3, 4, 5 };

		try {
			// System.out.println(arr[5]);
			//System.out.println("next");
			// } catch (NullPointerException e) {
			//Exceptions obj = new Exceptions();
			//obj.test();
			int a=5;
			int b=0;
			int c=a/b;

		}
		// System.out.println("in between try and catch");
		// catch (ArrayIndexOutOfBoundsException e) {
		// catch (NullPointerException e) {
		catch (Exception e) {
			// TODO: handle exception
			//System.out.println(e.getMessage());
			System.out.println(e.printStackTrace());
			//e.printStackTrace();
		}
		// System.out.println("hi");
	}

}

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why aboe gave below error at line 31?

The method println(boolean) in the type PrintStream is not applicable for the arguments (void)