Cameron Neiswender
asked on
Summarizing a percent by a grouped category
Hi, I am new to crystal reports, and picked up a half finished report form a predecessor. Looking to calculate a percent of usage for a category.
Structure looks like this.
GH1 - category summary - total hours for category
GH2 - nothing
GH3 - Item Summary - total hours for item, % for each item (summary of detail/potential)
Details - entry line for each item
Had two ways iu was trying to get this piece of information. Either getting a count of each item in a category and dividing the total hours by this and our set potential amount, or summarizing the percent, but i cannot get either of these to work.
any help is greatly appreciated
Structure looks like this.
GH1 - category summary - total hours for category
GH2 - nothing
GH3 - Item Summary - total hours for item, % for each item (summary of detail/potential)
Details - entry line for each item
Had two ways iu was trying to get this piece of information. Either getting a count of each item in a category and dividing the total hours by this and our set potential amount, or summarizing the percent, but i cannot get either of these to work.
any help is greatly appreciated
ASKER
The potential field is hard number 173, per each item, its not a field in the report
SO it should be
Sum({Detail Value}, {Summary Group}) / (Count({Detail Value}, {Summary Group}) * 173)
Sum({Detail Value}, {Summary Group}) / (Count({Detail Value}, {Summary Group}) * 173)
ASKER
So, This is what i have,
(Sum ({@VariableHrlyHours}, {EMEM.Equipment}) / (DistinctCount ({EMEM.Equipment},{@GroupC ombinedCat egories} )*173))
It is returning a value for the first item in the group, and for a value of 1/Nth of what it should be, N being the number of items in the group, i.e. 1/5th for a group with 5 items.
(Sum ({@VariableHrlyHours}, {EMEM.Equipment}) / (DistinctCount ({EMEM.Equipment},{@GroupC
It is returning a value for the first item in the group, and for a value of 1/Nth of what it should be, N being the number of items in the group, i.e. 1/5th for a group with 5 items.
Where did you put it?
It has to be in the group 3 header or footer.
mlmcc
It has to be in the group 3 header or footer.
mlmcc
ASKER
Putting it in the group 3 header gives me a value for each item, not for the group, but the value is still 1/Nth of what it should be
Design-Capture.PNG
Preview-Capture.PNG
Design-Capture.PNG
Preview-Capture.PNG
Can you show the detail section and take another snap shot?
mlmcc
mlmcc
ASKER
Preview with details
PPreview-with-details.PNG
PPreview-with-details.PNG
It looks like the totals are correct for the hours. Where is the problem with the value?
Is that the @Test% formula?
The value looks correct. If you want to display it as a % then set the format. You may have to multiply by 100 to move the decimal
mlmcc
Is that the @Test% formula?
The value looks correct. If you want to display it as a % then set the format. You may have to multiply by 100 to move the decimal
mlmcc
ASKER
the 76 % was existing, the %test formula is the one i created, it shows as 0.38 on the first section. What i am trying to get is a percent by category, i.e the 10 Wheel dump, (grey Bar). the value there is a summary of total hours for all items in the category, i need a percent by category, but cannot sum the percent of each item
How is the 76% calculated?
Change the %test to the below and show as a %. It will be 38.xx%
mlmcc
Change the %test to the below and show as a %. It will be 38.xx%
(Sum ({@VariableHrlyHours}, {EMEM.Equipment}) / (DistinctCount ({EMEM.Equipment},{@GroupCombinedCategories} )*173)) * 100
mlmcc
ASKER
Formula CalcEquip Usage and a format formula to add the *100 & "%"
Sum ({@VariableHrlyHours}, {EMEM.Equipment})/173
the 76% is correct, the .38 is that value divided by count in that category
attached is a slide with notes,
PPreview-with-detailsand-notes2.PNG
Sum ({@VariableHrlyHours}, {EMEM.Equipment})/173
the 76% is correct, the .38 is that value divided by count in that category
attached is a slide with notes,
PPreview-with-detailsand-notes2.PNG
ASKER CERTIFIED SOLUTION
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ASKER
That worked perfectly. Thank you for all of your help, it is truly appreciated
Which field is potential?
Sum({Detail Value}, {Summary Group}) / Sum(Potential Field{)
mlmcc