The most successful MSPs rely on metrics – known as key performance indicators (KPIs) – for making informed decisions that help their businesses thrive, rather than just survive. This eBook provides an overview of the most important KPIs used by top MSPs.
Why is my sum function not working properly?
I am trying to do a simple sum on the "Booking_Factor" column(int) and it is not summing at all as if nothing , the values are the same, any idea? Thank You.
SELECT distinct
RES.Description,
Available_Date,
--LOC.Scheduling_Location_ID,
--DEPT.Description,
--Day_Type_ID,
--Available_Time_Block_ID,
--Available_Time_Block_TS,
Start_Time,
End_Time,
Usual_Appt_Duration,
SUM(Booking_Factor)AS Capacity
-- AVAILBLOCK.Activity_Type_ID,
-- ELIG.Appointment_Category_ID AS Elig_Appointment_Category_ID,
--INELIG.Appointment_Category_ID AS Inelig_Appointment_Category_ID
FROM PM.Available_Days AVAILDAY WITH (NOLOCK)
LEFT JOIN PM.Available_Time_Blocks AVAILBLOCK WITH (NOLOCK) ON AVAILBLOCK.Available_Day_ID = AVAILDAY.Available_Day_ID
--LEFT JOIN PM.Scheduling_Locations LOC WITH (NOLOCK) ON LOC.Scheduling_Location_ID = AVAILDAY.Scheduling_Location_ID
--LEFT JOIN PM.Scheduling_Departments DEPT ON DEPT.Scheduling_Department_ID = AVAILDAY.Scheduling_Department_ID
LEFT JOIN PM.Resources RES WITH (NOLOCK) ON RES.Resource_ID = AVAILDAY.Resource_ID
--LEFT JOIN PM.Activity_Elig_Appt_Categs ELIG WITH (NOLOCK) ON ELIG.Activity_Type_ID = AVAILBLOCK.Activity_Type_ID
--LEFT JOIN PM.Activity_Inelig_Appt_Categs INELIG WITH (NOLOCK) ON INELIG.Activity_Type_ID = AVAILBLOCK.Activity_Type_ID
WHERE AVAILDAY.Available_Date = '2017-03-09'
AND RES.Description = 'REYNOLDS, EUGENE II'
group by
RES.Description,
Available_Date,
Start_Time,
End_Time,
Usual_Appt_Duration
Who is Participating?
Experts Exchange Solution brought to you by
Enjoy your complimentary solution view.
Get every solution instantly with Premium.
Start your 7-day free trial.
I wear a lot of hats...
"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.
Is you Available_Date column a date or a datetime data type? If the last one, then you should use a 24h interval to get all records for that day.
Also, you don't need the DISTINCT keyword since you're using GROUP BY:
Also, you don't need the DISTINCT keyword since you're using GROUP BY:
SELECT
RES.Description,
Available_Date,
Start_Time,
End_Time,
Usual_Appt_Duration,
SUM(Booking_Factor)AS Capacity
FROM PM.Available_Days AVAILDAY WITH (NOLOCK)
LEFT JOIN PM.Available_Time_Blocks AVAILBLOCK WITH (NOLOCK) ON AVAILBLOCK.Available_Day_ID = AVAILDAY.Available_Day_ID
LEFT JOIN PM.Resources RES WITH (NOLOCK) ON RES.Resource_ID = AVAILDAY.Resource_ID
WHERE AVAILDAY.Available_Date BETWEEN '20170309' AND '20170310'
AND RES.Description = 'REYNOLDS, EUGENE II'
GROUP BY
RES.Description,
Available_Date,
Start_Time,
End_Time,
Usual_Appt_Duration
Experts Exchange Solution brought to you by
Your issues matter to us.
Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.
Start your 7-day free trial
yes! the following is what worked:
SELECT
RES.Description,
Available_Date,
--LOC.Scheduling_Location_ID,
--DEPT.Description,
--Day_Type_ID,
--Available_Time_Block_ID,
--Available_Time_Block_TS,
--Start_Time ,
--End_Time,
--Usual_Appt_Duration,
sum( Booking_Factor)as capacity
-- AVAILBLOCK.Activity_Type_ID,
-- ELIG.Appointment_Category_ID AS Elig_Appointment_Category_ID,
--INELIG.Appointment_Category_ID AS Inelig_Appointment_Category_ID
FROM PM.Available_Days AVAILDAY
LEFT JOIN PM.Available_Time_Blocks AVAILBLOCK ON AVAILBLOCK.Available_Day_ID = AVAILDAY.Available_Day_ID
LEFT JOIN PM.Scheduling_Locations LOC WITH (NOLOCK) ON LOC.Scheduling_Location_ID = AVAILDAY.Scheduling_Location_ID
LEFT JOIN PM.Scheduling_Departments DEPT ON DEPT.Scheduling_Department_ID = AVAILDAY.Scheduling_Department_ID
LEFT JOIN PM.Resources RES ON RES.Resource_ID = AVAILDAY.Resource_ID
LEFT JOIN PM.Activity_Elig_Appt_Categs ELIG WITH (NOLOCK) ON ELIG.Activity_Type_ID = AVAILBLOCK.Activity_Type_ID
LEFT JOIN PM.Activity_Inelig_Appt_Categs INELIG WITH (NOLOCK) ON INELIG.Activity_Type_ID = AVAILBLOCK.Activity_Type_ID
WHERE AVAILDAY.Available_Date = '2017-03-08'
AND RES.Description = 'example MD, Name'
group by
RES.Description,
Available_Date
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
Microsoft SQL Server
From novice to tech pro — start learning today.
Experts Exchange Solution brought to you by
Enjoy your complimentary solution view.
Get every solution instantly with Premium.
Start your 7-day free trial.
Define in simple English what you wish to sum Booking_Factor by. RES.Description? Available_Date_ID?
Then eyeballeth all of the columns in your GROUP BY clause, especially Start_Time and End_Time. Are they unique? If yes, that kinda defeats the purpose of doing the SUM, and you'll have to remove those columns and possibly others to get the correct sum amount.