I am trying to do a simple sum on the "Booking_Factor" column(int) and it is not summing at all as if nothing , the values are the same, any idea? Thank You.
SELECT distinct RES.Description, Available_Date, --LOC.Scheduling_Location_ID, --DEPT.Description, --Day_Type_ID, --Available_Time_Block_ID, --Available_Time_Block_TS, Start_Time, End_Time, Usual_Appt_Duration, SUM(Booking_Factor)AS Capacity -- AVAILBLOCK.Activity_Type_ID, -- ELIG.Appointment_Category_ID AS Elig_Appointment_Category_ID, --INELIG.Appointment_Category_ID AS Inelig_Appointment_Category_ID FROM PM.Available_Days AVAILDAY WITH (NOLOCK) LEFT JOIN PM.Available_Time_Blocks AVAILBLOCK WITH (NOLOCK) ON AVAILBLOCK.Available_Day_ID = AVAILDAY.Available_Day_ID --LEFT JOIN PM.Scheduling_Locations LOC WITH (NOLOCK) ON LOC.Scheduling_Location_ID = AVAILDAY.Scheduling_Location_ID --LEFT JOIN PM.Scheduling_Departments DEPT ON DEPT.Scheduling_Department_ID = AVAILDAY.Scheduling_Department_ID LEFT JOIN PM.Resources RES WITH (NOLOCK) ON RES.Resource_ID = AVAILDAY.Resource_ID --LEFT JOIN PM.Activity_Elig_Appt_Categs ELIG WITH (NOLOCK) ON ELIG.Activity_Type_ID = AVAILBLOCK.Activity_Type_ID --LEFT JOIN PM.Activity_Inelig_Appt_Categs INELIG WITH (NOLOCK) ON INELIG.Activity_Type_ID = AVAILBLOCK.Activity_Type_IDWHERE AVAILDAY.Available_Date = '2017-03-09'AND RES.Description = 'REYNOLDS, EUGENE II'group by RES.Description, Available_Date, Start_Time, End_Time, Usual_Appt_Duration
>and it is not summing at all as if nothing
Define in simple English what you wish to sum Booking_Factor by. RES.Description? Available_Date_ID?
Then eyeballeth all of the columns in your GROUP BY clause, especially Start_Time and End_Time. Are they unique? If yes, that kinda defeats the purpose of doing the SUM, and you'll have to remove those columns and possibly others to get the correct sum amount.
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James Murphy
ozzy t
ASKER
yes! the following is what worked:
SELECT RES.Description, Available_Date, --LOC.Scheduling_Location_ID, --DEPT.Description, --Day_Type_ID, --Available_Time_Block_ID, --Available_Time_Block_TS, --Start_Time , --End_Time, --Usual_Appt_Duration, sum( Booking_Factor)as capacity -- AVAILBLOCK.Activity_Type_ID, -- ELIG.Appointment_Category_ID AS Elig_Appointment_Category_ID, --INELIG.Appointment_Category_ID AS Inelig_Appointment_Category_ID FROM PM.Available_Days AVAILDAY LEFT JOIN PM.Available_Time_Blocks AVAILBLOCK ON AVAILBLOCK.Available_Day_ID = AVAILDAY.Available_Day_ID LEFT JOIN PM.Scheduling_Locations LOC WITH (NOLOCK) ON LOC.Scheduling_Location_ID = AVAILDAY.Scheduling_Location_ID LEFT JOIN PM.Scheduling_Departments DEPT ON DEPT.Scheduling_Department_ID = AVAILDAY.Scheduling_Department_ID LEFT JOIN PM.Resources RES ON RES.Resource_ID = AVAILDAY.Resource_ID LEFT JOIN PM.Activity_Elig_Appt_Categs ELIG WITH (NOLOCK) ON ELIG.Activity_Type_ID = AVAILBLOCK.Activity_Type_ID LEFT JOIN PM.Activity_Inelig_Appt_Categs INELIG WITH (NOLOCK) ON INELIG.Activity_Type_ID = AVAILBLOCK.Activity_Type_IDWHERE AVAILDAY.Available_Date = '2017-03-08'AND RES.Description = 'example MD, Name'group byRES.Description, Available_Date
Define in simple English what you wish to sum Booking_Factor by. RES.Description? Available_Date_ID?
Then eyeballeth all of the columns in your GROUP BY clause, especially Start_Time and End_Time. Are they unique? If yes, that kinda defeats the purpose of doing the SUM, and you'll have to remove those columns and possibly others to get the correct sum amount.