asked on
Undefined variable problem
Just starting to learn oo php. Probably a simple problem.
Here is some of the code from header.php
Here is some of the code from dbIntranet.php
I keep getting an error:
Notice: Undefined variable: serverName in C:\inetpub\wwwroot\portal2
What's up?
Here is some of the code from header.php
$serverName = "server\\exactsqlexpress";
$connectionInfoIntranet = array( "Database"=>"intranet", "UID"=>"???", "PWD"=>"???");
$connectionInfoPpp = array( "Database"=>"ppp", "UID"=>???", "PWD"=>"???");
Here is some of the code from dbIntranet.php
include("header.php");
class dbIntranet {
private $connIntranet;
function __construct(){
$this->open_connection();
}
public function open_connection() {
$this->connIntranet = sqlsrv_connect($serverName, $connectionInfoIntranet); <-----LINE 13
}
I keep getting an error:
Notice: Undefined variable: serverName in C:\inetpub\wwwroot\portal2
What's up?
PHP
Last Comment
Robert Francis
ASKER CERTIFIED SOLUTION
THIS SOLUTION ONLY AVAILABLE TO MEMBERS.
View this solution by signing up for a free trial.
Members can start a 7-Day free trial and enjoy unlimited access to the platform.
ASKER
Would I not have to do the same thing for $connectionInfoIntranet?
ASKER
Oops, we commented at the same time
ASKER
Thanks for the lesson.
So you -could- do this to your class definition:
class dbIntranet {
private $connIntranet;
private $serverName; // New class property called serverName
function __construct($serverName){ // Change the constructor to accept a new parameter
$this->serverName = $serverName; // Copy the value of the parameter to the class property
$this->open_connection();
}
public function open_connection() {
$this->connIntranet = sqlsrv_connect($this->serverName, $connectionInfoIntranet); <-----LINE 13
}
...and then when you created a new instance of dbIntranet, you pass in your global variable:
$x = new dbIntranet($serverName);