asked on

Echo Multiple values from multiple records

Hi experts. I have a table in my sql server db with columns "DATE", "SHIFT", "AREA","PERSON1", "PERSON2", and "PERSON3". On my form page I have a table that performs multiple inserts. DATE and SHIFT are entered in all records and are the same value for each submission. So 3-10-17, MORNING, FRONT, PETER, DAN, JULIE will be the first record submitted and 3-10-17, MORNING, BACK, LUKE, JIM, KOBE would be the second submission. My main issue here is now I am doing a select statement to display these values in a php table but since the columns are the same if I DATE and SHIFT I can only show echo one record. I know this sounds confusing so refer to the image below and you will understand.

Dave Baldwin

No image. In addition, you may need to check if '3-10-17' is a valid DATE format. If it is not, then you can't sort or ORDER BY that column properly. You also may want to have an index 'auto-increment' column so that you will have a unique ID for each row that you can use for UPDATE statements.

Ray Paseur

3-10-17 is ambiguous. Do you want March 10 or October 3? The disambiguation rules may not be your friend here, so I would recommend not using this as a date string. You need to use the ISO-8601 format strings for all internal representations of date/time values.

Give yourself a little time with these articles -- they will show you exactly how to deal with a multitude of date/time questions!

Procedural
https://www.experts-exchange.com/articles/201/Handling-Date-and-Time-in-PHP-and-MySQL-Procedural-Version.html

Object-oriented
https://www.experts-exchange.com/articles/20920/Handling-Time-and-Date-in-PHP-and-MySQL-OOP-Version.html

Dave Baldwin

Here https://msdn.microsoft.com/en-us/library/ms186724.aspx is the T-SQL Date format info for MS SQL Server. It shows similar requirements. If you don't use one of the standard Date formats in a DATE column, then it probably won't INSERT and you can't use it in DATE arithmetic.

Dave Baldwin

In addition, using DATE as a column name can potentially cause problems because it is used by the server for other things. Here are the reserved words for T-SQL and ODBC. If I am going to use something like DATE in a column, I always modify it to something like DATEW so it does not match any reserved words.

peter Ojeda

ASKER

Sorry I was trying to put two images in and was clicking around. Must of accidently removed it.
select-results.PNG
selectsql.PNG

peter Ojeda

ASKER

Ok thankyou all for your comments. I have been using the y-m-d format for a while now with no problem as Ray pointed out I understand how it can become one.

Peos John

Can you please explain what is the output you are trying to get?

You have two records in your sample here with' 3-10-17'(database date format is yyyy-mm-dd) and MORNING.

Do you have problem with your INSERTS or SELECT that shows only one record?

peter Ojeda

ASKER

The select statement is where I am having an issue. I was just trying to display how it is in sql vs how it displays in my php page. I want it to look as it is in SQL. So based on date and Shift it will display all the results in a table format

Julian Hansen

SELECT 
  `DATE`, 
  `CREW`, 
  `SHIFT`,
  `LINE`,
  `LINE_NUM`,
  `PERSON_1`,
  `PERSON_2`,
  `PERSON_3`,
  `PERSON_4`
FROM
   `YourTableNameHere`
ORDER BY
  `DATE`, 
  `SHIFT`

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Note use of ` (Backticks) to get around conflict with DB reserved words. This is not endorsing the use of reserved words but demonstrate you can use them without confusing the DB.

The above query will give you the results of the SQL table in the second image in the right order. You can then simply loop through the result set and output the values.

I am not sure if I have understood your requirements properly but this is my best guess (based on information provided).

Dave Baldwin

I don't believe that MS SQL Server supports the use of backticks.

This page https://msdn.microsoft.com/en-us/library/ms189822.aspx says...
"Although it is syntactically possible to use SQL Server reserved keywords as identifiers and object names in Transact-SQL scripts, you can do this only by using delimited identifiers."

Here is a confusing page about 'delimiters':
https://technet.microsoft.com/en-us/library/ms176027(v=sql.105).aspx

peter Ojeda

ASKER

Thank you yes I was able to perform this with a while loop and without the back ticks. Any recommendations on how to pass two results into my select statement? I am able to pass the date into there (which I am going to change from just date) but I also want to pass the shift into there.
On my PHP form I have this

 <a href="CE_CREWA_SELECT2.php?ID=<?php echo $result["DATE"] ->format("Y-m-d");?>">View/Edit</a>

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which passes the date to the query, and the query it is $stmt = "SELECT * FROM CE_MANNING WHERE DATE = ? ";. This works but I want to pass date as well as SHIFT.

Julian Hansen

I don't believe that MS SQL Server supports the use of backticks.

I was going on this (as it was not clear on TA's selected)

I have a table in my sql server db

MS SQL uses [ ] so

SELECT 
  [DATE], 
  [CREW], 
  [SHIFT],
  [LINE],
  [LINE_NUM],
  [PERSON_1],
  [PERSON_2],
  [PERSON_3],
  [PERSON_4]
FROM
   [CE_MANNING]
ORDER BY
  [DATE], 
  [SHIFT]

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To your question - you want to use the AND operator in the WHERE clause

SELECT * FROM [CE_MANNING] WHERE [DATE]=? AND [SHIFT]=?

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Given your link you are passing this to another script

<a href="CE_CREWA_SELECT2.php?ID=<?php echo $result["DATE"] ->format("Y-m-d");?>">View/Edit</a>

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To say how the script changes we need to see it but to pass the additional parameter

<a href="CE_CREWA_SELECT2.php?ID=<?php echo $result["DATE"]->format("Y-m-d");?>&amp;shift=<?php echo $result["SHIFT"];?>">View/Edit</a>

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peter Ojeda

ASKER

The code below is the php script I am using to do the select statement that I am attempting to pass the date and Shift into. I am able to pass just the date with the code previously shown and if I remove Shift from the select query. I am not sure if I am messing up the select query or the passing of the variable

  $strID = null;

   if(isset($_GET["ID"]))
   {
	   $strID = $_GET["ID"];
   }
  
   $connectionInfo = array("Database"=>$dbName, "UID"=>$userName, "PWD"=>$userPassword, "MultipleActiveResultSets"=>true);

   $conn = sqlsrv_connect( $serverName, $connectionInfo);

   if( $conn === false ) {
      die( print_r( sqlsrv_errors(), true));
   }

	$stmt = "SELECT * FROM TABLLE WHERE DATE = ?, AND SHIFT= ? ";
	$params = array($strID);

	$query = sqlsrv_query( $conn, $stmt, $params);

	$result = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC)

?>

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ASKER CERTIFIED SOLUTION

Julian Hansen

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Dave Baldwin

Maybe I'm lost but 'sqlsrv_fetch_array' only returns one row at a time. I only see you calling it once. I though you wanted multiple rows.

http://php.net/manual/en/function.sqlsrv-fetch-array.php

peter Ojeda

ASKER

Hi Julien I attempted to do it the way you just said but I'm still getting an error message and then some. View below what is happening now. I have no clue what I am doing wrong.

<?
$strID = null;
// DEFAULT RETURN
$result = array();

// GET PARAMS SAFELY
$strID = isset($_GET["ID"]) ? $_GET["ID"] : false;
$strSHIFT = isset($_GET["SHIFT"]) ? $_GET["SHIFT"] : false;
// ONLY PROCEED IF WE GOT VALID PARAMETERS
if ($strID && $strSHIFT) {
  $connectionInfo = array(""=>$dbName, ""=>$userName, ""=>$userPassword, "MultipleActiveResultSets"=>true);
  $conn = sqlsrv_connect( $serverName, $connectionInfo);
  
  if( $conn === false ) {
    die( print_r( sqlsrv_errors(), true));
  }

  // SET UP QUERY WITH PARAMETERS
  $stmt = "SELECT * FROM [CE_MANNING] WHERE [DATE] = ?, AND [SHIFT]= ? ";
  
  // ADD PARAMETER VALUES
  $params = array($strID, $strSHIFT);
  
  $query = sqlsrv_query( $conn, $stmt, $params);
  
  $result = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC);
}
// RETURN DATA
?>
<table width="500" border="1" id="myTable">
  <tr>
    <th width="91"> <div align="center">ID</div></th>
    <th width="91"> <div align="center">Date</div></th>
  </tr>
<?php
while($result = sqlsrv_fetch_array($query, SQLSRV_FETCH_ASSOC))
{
?>
  <tr>
	<td align="center" width="120px" nowrap> <div align="center"><?php echo $result["DATE"] ;?></div></td>
	<td align="center" width="120px" nowrap> <?php echo $result["SHIFT"];?></td>
  </tr>
<?php
}
?>
</table>
<br>
<br>
<?php
sqlsrv_close($conn);
?>
</div>
</article>
</body>
</html>

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example-3_12_17.PNG

SOLUTION

Ray Paseur

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peter Ojeda

ASKER

Ray, thankyou for all your input. Always thought the error messages did not help too much but I will definitely try that. And I removed most of the css just to save space. Added the php trigger error(which I am very thankful for showing me) and the error message below is now displayed.
3_12_17ex.PNG

SOLUTION

Julian Hansen

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