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DateDiff in hours , minutes and seconds between two dates should include only working hours Crystal Report


I am working on a crystal report to show the Responded and Completed time of work orders based on work order created date and Responded Date. Created date and completed date
I want to display  the difference of dates in hours minutes and seconds which should only include working hours

WOrking hours window -  Mon - Fri 7:30 am - 5:00 pm

Thanks !
Crystal ReportsMicrosoft SQL Server

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Mike McCracken

8/22/2022 - Mon

IN crystall you would need to perform the calculations
The logic shoukd exclude the first day of the work order and the last when the work order completed the says in between multiplied by 9.5 hours.
Then adding the difference in time between work order entry and end of day. Plus the time diff from start of day till when the work order was completed.

The combination of getting number of days in the wororder....

I.e. Processing wise...........
Nitin Sontakke

Efficient and maintainable would be a sql server scalar udf receiving two dates and returning a value, i suppose!

There are some well known Crystal formula by Ken Hamady (here) for calculating working hours.
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Jim Horn

Good luck with that.  The only way you're going to be able to come up with a rock-solid answer is to build a SQL Server Calendar Table , but build it hourly (half hour?) instead of daily like in the article, with a column 'open for business' that identifies if the place is open or not.  

Otherwise you could come up with a function that handles the Mon - Fri 7:30 am - 5:00 pm, but it will not handle any exception to that such as staying open and closing early.

Recommend doing a Google Search for 'steve wake sql', as there's a SQL expert named Steve Wake who worked at Chipotle and did a presentation at PASS Summit 2015 on how to pull off a calendar table by hour.  Maybe he published some of this presentation for download.
Mike McCracken

The formulas from Ken Hamady do work.  I have used them in the past.  They can be a bit of a pain to get working.

Mike McCracken

Here is a sample report with working formulas

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I have the below logic from other reports, it is calculating the hours by excluding the week end (Saturday & sunday)
but not calculating for working hours. Mon - Fri (7:30 am - 5:00 pm)

How can i add the logic to it to calculate time only with working hours

Function CF_getDuration (StartingDate As DateTime, EndingDate As DateTime, Sought As String) As String


DIM Days as number,Hours as number, Minutes as number, Seconds as number
DIM TotalSeconds as number
DIM WeekendDayCount as number
DIM NewEndingDate as DateTime

' Get the number of business days between the 2 dates
WeekendDayCount = DateDiff("ww", StartingDate, EndingDate, crSaturday) + DateDiff ("ww", StartingDate, EndingDate, crSunday)

' Set a new end date that removes the business day count
NewEndingDate = EndingDate - WeekendDayCount

'Determine the total number of seconds

'calc days
Days=Seconds \ SECONDS_PER_DAY 'integer division
Seconds=Seconds-Days*SECONDS_PER_DAY 'remove days

'calc hours
Hours=Seconds \ SECONDS_PER_HOUR 'integer division
Seconds=Seconds-Hours*SECONDS_PER_HOUR 'remove hours

'calc minutes
Minutes=Seconds \ SECONDS_PER_MINUTE 'integer division
Seconds=Seconds-Minutes*SECONDS_PER_MINUTE 'remove minutes

IF Sought = "d:h:m" THEN
    'CF_TEST_DMHS=Cstr(Days,0) & ":" & CStr(Hours,0) & ":" & Cstr(Minutes,0) & ":" & Cstr(Seconds,0)
    CF_getDuration=Cstr(Days,0) & ":" & CStr(Hours,0) & ":" & Cstr(Minutes,0)

ELSEIF Sought = "d" THEN
    ' Return total days, and allow fractional numbers
    Days = TotalSeconds / SECONDS_PER_DAY
    CF_getDuration = CStr(Days,6)

ELSEIF Sought = "h" THEN
    ' Return total hours, and allow fractional numbers
    Hours = TotalSeconds / SECONDS_PER_HOUR
    CF_getDuration = CStr(Hours,6)

ELSEIF Sought = "n" THEN
    ' Return total minutes, and allow fractional numbers
    Minutes = TotalSeconds / SECONDS_PER_MINUTE
    CF_getDuration = CStr(Minutes,6)

Mike McCracken

Did you look at the formulas in the report I added?

Did you look at the formulas that PortletPaul linked to on Ken Hamady's web site?


Yes, i did look the formulas in the report but I am getting all negative values in hours..  It doesn't seem to be working correctly.
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Double check where you're using the start and end dates.  The obvious guess would be that you have them backwards.  If you're not sure, post your formulas, or the actual report (the .RPT file), so that we can take a look at them.

 Having said that, if you're looking for the difference down to the second, Ken's formulas give you the difference in hours, so that's probably only a partial solution (Unless the result includes fractions of hours.  I haven't checked).  I didn't look at the report that mlmcc posted, so I don't know if he calculated down to the second.

Mike McCracken

Can you post your report?

If not can you copy the formulas here


Below is the formula I am using from the above attached TimeToComplete.rpt

 TASKS.OPENDATE  =  2017-03-01 14:39:04.000
TASKS.COMPLETED = 2017-03-02 14:40:00.000

 Attached is the report pls look for TimeCompleted formula,
 I am getting the average in the report
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Mike McCracken

I don't see the formulas or an attachment


Please find the attached report
Mike McCracken

The formula is working.  The variable Days is an intermediate value and does NOT correspond to the number of days the WO took.

All I had to do was to uncomment the NumDays conversion to a string and eliminate the Days conversion and it works

This is the new last line of the formula
CStr(NumDays,0) + " days " +  CStr(Numhours,0) & ":" + CStr(NumMinutes, "00") & ":" + CStr(NumSeconds,"00");

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I need the result in d: h:m which I had in my code before I sent..   If it is only 5 min ,  formula should return 0:0:05 ,  
If it is 65 min then 0:1:05 and  if it is more than one day and 1 hour 45 min then 1:1:45

I need other formula to return only hours for the bar graph

Thanks !
Mike McCracken

My correction should display it as x days hh:mm:ss

What other formula are you referring to?
The chart will only show the count of the records.  The hour values won't enter into it at all.
What are you trying to show with the chart?

Mike McCracken

Is this what you want for the display?

CStr(NumDays,0) + ":" +  CStr(Numhours,"00") & ":" + CStr(NumMinutes, "00") & ":" + CStr(NumSeconds,"00");

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I have used the below formula but still i get negative values

Date({TASKS.OPENDATE}  = 2017-03-08 19:11:24.000
Date{TASKS.COMPLETED} = 2017-03-10 23:53:27.000

Result in negative values :  -17:00:00:-57

DateVar Array Holidays := [
Date (2017,1,1),
Date (2017,2,20),
Date (2017, 5, 29)

Local DateVar Start := Date({TASKS.OPENDATE});
Local DateVar End := Date({TASKS.COMPLETED});
Local NumberVar Weeks;
Local NumberVar Days;
Local Numbervar Hol;
DateVar Array Holidays;

Weeks:= (Truncate (End - dayofWeek(End) + 1
- (Start - dayofWeek(Start) + 1)) /7 ) * 5;

Days := DayOfWeek(End) - DayOfWeek(Start) + 1;
Days := Days + (if DayOfWeek(Start) = 1 then 1 else 0);
Days := Days + (if DayOfWeek(End) = 7 then 1 else 0);

Local NumberVar i;
For i:= 1 to Count (Holidays) do
    if DayOfWeek ( Holidays(i) ) in 2 to 6 and
       Holidays(i) in start to end then

Days := Weeks + Days - Hol;
TimeVar SetStart := TimeValue("7:30");
TimeVar SetEnd := TimeValue("17:00");
TimeVar StartTime := TimeValue({TASKS.OPENDATE});
TimeVar EndTime := TimeValue({TASKS.COMPLETED});
Local NumberVar NumDays;
Local NumberVar NumHours;
Local NumberVar NumMinutes;
Local NumberVar NumSeconds;

NumSeconds := (Days * ((SetEnd - SetStart) / 3600)
                - ((SetEnd - EndTime) / 3600)
                - ((StartTime - SetStart) / 3600)) * 3600;

//NumDays := NumSeconds \ (9.5 * 60* 60);
//NumSeconds := NumSeconds MOD (9.5 * 60* 60);

NumHours := NumSeconds \ 3600;
NumSeconds := NumSeconds MOD 3600;
NumDays := NumSeconds \ 60;
NumSeconds := NumSeconds MOD 60;

//CStr(NumDays,0) + " days " +
CStr(NumDays,0) + ":" +  CStr(Numhours,"00") & ":" + CStr(NumMinutes, "00") & ":" + CStr(NumSeconds,"00");
Mike McCracken

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