# Finding Divisors

In the code below it is not registering float values - for example if it divides 4 by 3 it is registering 1 as an answer (if you enter 4 when it loops up to 3 it doesn't record the float value).

I want to store the float value so I can see if it is a divisor or not.

``````#include <iostream>
#include <cmath>

bool is_integer(float number) {
return std::floor(number) == number;
}

int divisors(int number) {
int i = 1;
float result;
for (i = 1; i<= number; i++) {
result = number / i;
std::cout << i;
std::cout << result;
std::cout << "\n";
}
}

int main()
{
int counter = 1;
int number;
int number_divisors;

std::cout << "Enter a number to find the divisors";
std::cin >> number;

number_divisors = divisors(number);

return 0;
}``````
phoffric

float f = number:

Try using f instead of number when calculating result.
Integer math will do this job faster than floating point.  Only numbers up to the square root of the number under test must be examined.  Example pseudocode below ...

``````for k = 2 to sqrt(testnumber)
if [testnumber mod k) == 0] {
print (k, "is a factor of", testnumber)
print (testnumber/k, "is a factor of", testnumber)
}
next k``````
result = number / i;
you could make it 2 statements as suggested by phoffric or do

``result = ((float)number )/ i;``

this would 'cast' the nominator to float and the division result is float as well.

Sara
``number_divisors = divisors(number);``

you seem to be expecting divisors() to return something but I don't see a return statement in the function.

``````float result;
for (i = 1; i<= number; i++) {
result = number / i;
std::cout << i;
std::cout << result;
std::cout << "\n";
}
}``````

also if you are trying to count divisors the logic you've used is not going to do any counting..... for that you have to do what Dr.Klahn has suggested