troubleshooting Question

How to structure query with count aggregate

Avatar of ugeb
ugebFlag for United States of America asked on
DatabasesMongoDBSQL
4 Comments1 Solution277 ViewsLast Modified:
I'm working on a challenge on HackersRank, and brushing up on my SQL skills.  I'm given the following table 'Challenges':

Simple table with hackers and their challengesSo the challenge_id is unique in the table, and hacker_id is the id of the hacker who created the challenge.   I'm trying to meet the challenge step by step, so right now I'm working on what will be an inner query.  

What I'm trying to figure out is how to get a list of hacker_id's where there is no other hacker that created that exact number of challenges.  
Select c2.hacker_id, Count(c2.challenge_id) cnt2 
From Challenges as c2 
Group By c2.hacker_id 
Order By cnt2 Desc;
This query works in getting the number of challenges created by each hacker.  I don't really care about the order in this case, I just have the Order By for viewing intermediate results.

Next, I'm trying to get a list of EITHER all hackers who created a unique number of challenges or who DIDN'T create a unique number of challenges.  Either way works.  Playing around, I tried this:
Select *, count(ch.cnt2) cnt1 From 
(Select c2.hacker_id, Count(c2.challenge_id) cnt2 
From Challenges as c2 
Group By c2.hacker_id) ch, 
Challenges c1
Group By cnt1;
I received the error:
ERROR 1056 (42000) at line 1: Can't group on 'cnt1'
.  

Why can't I group on cnt1?


I want the query to either include or exclude hackers without a unique number of challenges.  
Without changing the approach I'm taking, how can I accomplish this query?
ASKER CERTIFIED SOLUTION
pcelba

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