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php date function ( diffrence between two dates )

BR asked
Last Modified: 2017-03-28
Dear Experts,

I'd like to find the time duration in days and months between two dates.

I have two dates

echo $today = date('Y-m-d');
echo "<br>";
echo $seconddate =  "2017-10-18";
echo "<br>";
echo $diffrence = ($seconddate - $today);

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but it doesn't work. what should I do?
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Hello, try this:

$date1 = "now";
$date2 = "2017-10-18";

$diff = abs(strtotime($date2) - strtotime($date1));

$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

printf("%d years, %d months, %d days\n", $years, $months, $days);

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BRDigital Marketing


thank you SniperCode Sheva
You are welcome.
Most Valuable Expert 2011
Author of the Year 2014

The correct answer here is the first comment from Thomas.  It's an anti-practice to write your own date/time arithmetic, especially because it will often be wrong in months that do not have 30 days, in leap years, or across daylight savings time.  Instead use the built-in PHP functionality.

You can learn more about the ways we handle date/time values in this article.

You can get better answers here at E-E if you search the articles first, and if you leave your questions open a bit longer.  I would recommend leaving your questions open for at least 24 hours.

I do not recommend using the accepted solution in a deployed application.
BRDigital Marketing


Thank you Ray Paseur
You are right
Thank you very much

I will use the first answer

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