php date function ( diffrence between two dates )

Hello, try this:

<?php
$date1 = "now";
$date2 = "2017-10-18";

$diff = abs(strtotime($date2) - strtotime($date1));

$years = floor($diff / (365*60*60*24));
$months = floor(($diff - $years * 365*60*60*24) / (30*60*60*24));
$days = floor(($diff - $years * 365*60*60*24 - $months*30*60*60*24)/ (60*60*24));

printf("%d years, %d months, %d days\n", $years, $months, $days);
?>

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You are welcome.

The correct answer here is the first comment from Thomas.  It's an anti-practice to write your own date/time arithmetic, especially because it will often be wrong in months that do not have 30 days, in leap years, or across daylight savings time.  Instead use the built-in PHP functionality.

You can learn more about the ways we handle date/time values in this article.
https://www.experts-exchange.com/articles/20920/Handling-Time-and-Date-in-PHP-and-MySQL-OOP-Version.html

You can get better answers here at E-E if you search the articles first, and if you leave your questions open a bit longer.  I would recommend leaving your questions open for at least 24 hours.

I do not recommend using the accepted solution in a deployed application.