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show child records separated by commas

Black Sulfur
Black Sulfur asked
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Last Modified: 2017-03-28
I apologize if the title of the question doesn't match the question but I didn't know how else to describe it. Here is an example of my database table which shows the item and an ID. The ID from the below table is actually from a defect table which has an ID and description. This is from a previous question I posted on EE where I was selecting reasons via checkboxes. For simplicity I have used "car" and "bike". In the real world these would be unique identifiers.

Item     Defect
  car          5
  car          3
  car          7
  bike        9
  bike        2
  bike        5

I want to present this data in a html table that would look like this:

Car      Scratch, Broken window, burst tyre
Bike    Broken light, Missing seat, Scratch

I tired using GROUP BY which helped to just show one of each thing instead of doing this:

Car
Car
Car

but then it doesn't show all of the reasons, it only shows one.

My current SQL:

SELECT `product_no`, `commit_date`, `non_green_desc` FROM `non_green` AS ng INNER JOIN `non_green_reasons` AS ngr ON ng.`ng_id` = ngr.`ng_id` WHERE `complete_date` = ? GROUP BY `tank_no`

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Most Valuable Expert 2011
Author of the Year 2014

Commented:
Might be easier to get this in PHP instead of trying to do it all in MySQL.  Or maybe use two queries.  I think you want to get three rows for Car, but just display Car one time, and only display that column again when its value changes to Bike.  It's a little bit of logic, but only a little.

Also, you can put your questions into more than one Topic Area.  The MySQL topic area seems appropriate for this.

Author

Commented:
Yes, that's it. I want to get three rows but only show Car once.

Author

Commented:
I THINK I have to use a multidimensional array. I am going to try play around with that....
Most Valuable Expert 2011
Author of the Year 2014

Commented:
Most of this is just setup.  The moving parts start at the end of the script at line 72.
https://iconoun.com/demo/temp_black_sulfur.php
<?php // demo/mysqli_example.php
/**
 * https://www.experts-exchange.com/questions/29012010/show-child-records-separated-by-commas.html
 */
error_reporting(E_ALL);
echo '<pre>';


// DATABASE CONNECTION AND SELECTION VARIABLES - GET THESE FROM YOUR HOSTING COMPANY
$db_host = "localhost"; // PROBABLY THIS IS OK
$db_name = "??";
$db_user = "??";
$db_word = "??";

// OPEN A CONNECTION TO THE DATA BASE SERVER AND SELECT THE DB
$mysqli = new mysqli($db_host, $db_user, $db_word, $db_name);

// DID THE CONNECT/SELECT WORK OR FAIL?
if ($mysqli->connect_errno)
{
    $err
    = "CONNECT FAIL: "
    . $mysqli->connect_errno
    . ' '
    . $mysqli->connect_error
    ;
    trigger_error($err, E_USER_ERROR);
}


// CREATING A TABLE FOR OUR TEST DATA
$sql
=
"
CREATE TEMPORARY TABLE item_defects
( id     INT         NOT NULL AUTO_INCREMENT PRIMARY KEY
, name   VARCHAR(24) NOT NULL DEFAULT ''
, d_key  INT NOT NULL DEFAULT 0
)
"
;
$mysqli->query($sql);

$mysqli->query("INSERT INTO item_defects (name, d_key) VALUES ('car', 5)");
$mysqli->query("INSERT INTO item_defects (name, d_key) VALUES ('car', 3)");
$mysqli->query("INSERT INTO item_defects (name, d_key) VALUES ('car', 7)");

$mysqli->query("INSERT INTO item_defects (name, d_key) VALUES ('bike', 9)");
$mysqli->query("INSERT INTO item_defects (name, d_key) VALUES ('bike', 2)");
$mysqli->query("INSERT INTO item_defects (name, d_key) VALUES ('bike', 5)");

// CREATING A TABLE FOR OUR TEST DATA
$sql
=
"
CREATE TEMPORARY TABLE defects
( id     INT         NOT NULL AUTO_INCREMENT PRIMARY KEY
, d_key  INT         NOT NULL DEFAULT 0
, defect VARCHAR(24) NOT NULL DEFAULT ''
)
"
;
$mysqli->query($sql);

$mysqli->query("INSERT INTO defects (d_key, defect) VALUES (5, 'Scratch')");
$mysqli->query("INSERT INTO defects (d_key, defect) VALUES (3, 'Broken Window')");
$mysqli->query("INSERT INTO defects (d_key, defect) VALUES (7, 'Burst Tyre')");
$mysqli->query("INSERT INTO defects (d_key, defect) VALUES (9, 'Broken Light')");
$mysqli->query("INSERT INTO defects (d_key, defect) VALUES (2, 'Missing Seat')");


$sql = "SELECT name, defect FROM item_defects, defects WHERE item_defects.d_key = defects.d_key ORDER BY name DESC";
$res = $mysqli->query($sql);

$out = [];
$old = FALSE;
while ($row = $res->fetch_object())
{
    if ($row->name != $old)
    {
        $old = $row->name;
        $out[$row->name] = ucfirst($row->name) . ': ' . $row->defect;
    }
    else
    {
        $out[$row->name] .= ', ' . $row->defect;
    }
}

var_dump($out);

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Author

Commented:
Cool. So, I got this to work using my data and var_dump($out) but when trying to put it into a table it just shows one reason, instead of all of them.

 $old = $row->name;
echo "<tr>";
echo "<td>" . $out[$row->name] = ucfirst($row->name) . "</td>";
echo "<td>" . $row->defect . ", " . "</td>";
echo "</tr>";

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Most Valuable Expert 2011
Author of the Year 2014
Commented:
This problem has been solved!
(Unlock this solution with a 7-day Free Trial)
UNLOCK SOLUTION

Author

Commented:
That's perfect! Now all I have to do is really look at your code and figure out how and why it works exactly. No point in just using it if I don't understand it.
Most Valuable Expert 2011
Author of the Year 2014

Commented:
By way of explanation, we SELECT two columns from the database: name, defect.  We keep one instance of the name in the array key in $out, and we concatenate the instances of defect in the array value associated with that key.  This gives us a key => value association that makes for easy reorganization into a tabular display.

Author

Commented:
Thanks, Ray. I need another <td> but can't seem to show data from a third column in the database. Must I open a related question or ask here?
Most Valuable Expert 2011
Author of the Year 2014

Commented:
Might be worth another question.  If you can post your CREATE TABLE statement so we can see the column names and data types, that might be helpful.  If you can tell us what the third column is named, that will help, too.

Author

Commented:
Cool, will do so.
Most Valuable Expert 2011
Author of the Year 2014

Commented:
10-4, will look for the Q

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