troubleshooting Question

How to insert Commitment dates for each unit

Avatar of Crazy Horse
Crazy HorseFlag for South Africa asked on
8 Comments1 Solution55 ViewsLast Modified:
I had this question after viewing Adding additional variables to key => value association.

Hopefully this will be the last piece of the puzzle. I have text fields for each unit where a commitment date must be entered. I am using a foreach loop but when I var_dump it I can see way too many units.

Here is my html table. I am storing the unit key in a hidden field

<td><input type="text" class="form-control" name="commit_date[]" placeholder="Commitment date" id="date"><input type="hidden" name="u_key[]" value="{$thing}"></td>

The UPDATE query :

foreach($_POST['commit_date'] as $commitdate) {
$stmt = $link->prepare("UPDATE `units` SET `commit_date` = ? WHERE `u_key` = ?");
$stmt->bind_param("si", $commitdate, $_POST['u_key']);

When testing, if I var_dump the commitment date, I get three dates for 3 text fields and the output matches what I inputted. The units however looked like this.

array(3) { [0]=> string(6) "905467" [1]=> string(6) "675483" [2]=> string(6) "501786" } array(3) { [0]=> string(6) "905467" [1]=> string(6) "675483" [2]=> string(6) "501786" } array(3) { [0]=> string(6) "905467" [1]=> string(6) "675483" [2]=> string(6) "501786" }
Crazy Horse

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