Question regarding to $.ajax() with type "POST" vs $.post()

Hi Experts

I came across this scenario which I can do a post with JQuery ajax() or post(). I am not sure which one to use. I read some information from web but I believe the information wasn't correct because the website mentioned that $.post() only has success callback but I believe it has other function from this link: which mentioned that "The jqXHR.success(), jqXHR.error(), and jqXHR.complete() callback methods are removed as of jQuery 3.0. You can use jqXHR.done(),, and jqXHR.always() instead."

Now I am kind of confused as to which one to use. I will provide some feedback of what I am trying to do perhaps it will be easier to find the correct method for me. I have a login page that will take inputs from users (userID and password). I am trying to post the information to another page which it will validate user's input. If information is correct then it will return something  along the line of success() callback.

Rest of my pages will follow the same post structure. I need some suggestions as to which post should I use. Thanks
Kinderly WadeprogrammerAsked:
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Leonidas DosasCommented:
I suggest you to use $.post. As you described your intensions are specific without other feature like errors cache etc..
Julian HansenCommented:
You can use either $.post is just a short hand for $.ajax. If you are going to be doing standard POST the $.post is fine - if you need to manipulate headers and disable / enable fringe functionality then you use $.ajax.

Personally I always use $.ajax mainly out of habit but also because it gives consistency to my code.
As for the success done  fail etc. as of jQuery 1.5 all jQuery Ajax methods support the promise interface (if you want to know more about Promises you can read about them here

 .success, .error and .complete are removed as of jQuery 3.0 so you should rather use the .done(), .fail() and .always() callbacks.

You can read more about this here

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Kinderly WadeprogrammerAuthor Commented:
Thanks all for the feedback. I will keep them all under $ajax
Julian HansenCommented:
You are welcome.
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