SQL CASE Statement Check to see if Field Contains Alpha Characters
How can I use a CASE statement to check if a field contains alpha characters?
Ex
CASE F1 CONTAINS [A], [B] ....
Ex
CASE F1 CONTAINS [A], [B] ....
Nitin Sontakke
Can you provide some sample data please? What exactly are you trying achieve would be nice to know. Why I say this? Simple. For example, if you are trying to see if there is a alpha in otherwise expected to be a numeric value, there are functions to see if a value is numeric. Then this function can be used with NOT operator. Hope you get the point.
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And here is a complete demonstration...time gone in typing...
This is case insensitive.
This is case insensitive.
declare @temp table
(
[column1] varchar(10)
)
insert into @temp values
('A5689')
,('i5689')
,('5689')
,('56B89')
,('5689')
,('56J89')
,('2017-09-01')
,('5689L')
select *
from @temp
where [column1] like '%[A-Za-z]%'
select [column1], case when [column1] like '%[A-Za-z]%' then 1 else 0 end [HasAlpha]
from @temp
Just a comment: CASE is an expression, not a statement.
Do you mean only alpha chars? Including a space as valid as well:
SELECT F1, CASE WHEN F1 LIKE '%[^a-z ]%' THEN 'Not only alpha' ELSE 'only alpha' END
...
SELECT F1, CASE WHEN F1 LIKE '%[^a-z ]%' THEN 'Not only alpha' ELSE 'only alpha' END
...