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Draw diagram with locations of u and v determining the base of the triangle and w the apex.
Let x be the distance from w to p, the location of the load.
Let theta be the angle from the base at u to p.
Let phi be the angle from the base at v to p.
Let alpha be the angle from a horizontal at w to p.
Then the x components of the torques are
325 u cos theta
625 v cos phi
x w cos alpha
And the y components are
325 u sin theta
625 v sin phi
w x sin alpha
So we have six equations and seven unknowns, Get more information from geometry. Here we know that the triangle is 900 units on a side so that
325 sin theta + 625 cos phi = 900
325 cos (60 – theata) + x cos (alpha – 60) = 900
635 cos(60 – phi + x cos (120 – alpha) = 900
Solve these simultaneous equations being careful of the signs and converting degree to and from radians.