How do I add a new column to my already bound Gridview?

I've got a VB 2015 / ASP app that features a Gridview  displaying 6 columns of data via a SQL query.
I wish to add a new column at runtime, and poke in a text string based off cell text in column1(0 based)
Here's what my aspx Gridview section looks like:
   <asp:GridView ID="GridView1" runat="server" AllowSorting="True" AutoGenerateColumns="False" DataSourceID="SqlDataSource1" Height="486px" Width="661px">
                    <asp:BoundField DataField="spid" HeaderText="spid" SortExpression="spid" />
                    <asp:BoundField DataField="Login" HeaderText="Login" ReadOnly="True" SortExpression="Login" />
                    <asp:BoundField DataField="DB" HeaderText="DB" ReadOnly="True" SortExpression="DB" />
                    <asp:BoundField DataField="SERVER" HeaderText="SERVER" SortExpression="SERVER"/>
                    <asp:BoundField DataField="LOGIN TIME" HeaderText="LOGIN TIME" ReadOnly="True" SortExpression="LOGIN TIME"/>
                    <asp:BoundField DataField="USER COUNT" HeaderText="USER COUNT" ReadOnly="True" SortExpression="USER COUNT"/>
                    <asp:TemplateField HeaderText="SITE"   runat="server"></asp:TemplateField>

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In my code behind, I have a For loop where I'm doing some gridview manipulation such as cell coloring..etc
and I thought maybe I could do something similar to:
For i = 0 To GridView1.Rows.Count - 1
nameToCheck = GridView1.Rows(i).Cells(1).Text
nameToCheck = nameToCheck.Trim()

If nameToCheck = "MYNAME" Then GridView1.Rows(i).Cells(5).Text = "ME"

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Here's a snippet of what the grid looks like at runtime:
I want to query cell#2 for a value, and depending on the result, poke some text into my new column/cell...
make sense?
Am I even remotely close??
Richard GouetteIT ManagerAsked:
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Pawan KumarDatabase ExpertCommented:
Please use like below -
BoundField mynewcolumn= new BoundField();
mynewcolumn.DataField = "Field Name from Datatable";
mynewcolumn.Headertext = "New column Header";

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Richard GouetteIT ManagerAuthor Commented:
I did something similar:
        Dim site_field As New BoundField()
        site_field.HeaderText = "SITE"

I have a Column header showing in column#6, but, cannot figure out the binding portion, etc
Pawan KumarDatabase ExpertCommented:
The value you want to show in the columns is coming from datatable ?
That value needs to be bind.
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Richard GouetteIT ManagerAuthor Commented:
No, it would be some text that I'm giving it explicitly in code behind.

If nameToCheck = "MYNAME" Then GridView1.Rows(i).Cells(5).Text = "ME"

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Pawan KumarDatabase ExpertCommented:
Please try this-

Dim site_field As New BoundField()
site_field.HeaderText = "SITE"
site_field.DataField= "ME"

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Richard GouetteIT ManagerAuthor Commented:
When I try that code under my Page_Load event, the gridview disappears..

Is it even possible to bind a new column to my existing gridview, if the gridview is already  bound to a SQL DataSource?
Pawan KumarDatabase ExpertCommented:
Add a hardcoded condition to your SQL itself like below-

SELECT yourcolumns, 'ME' extracol
FROM yourtableName

then you can use like

im site_field As New BoundField()
site_field.HeaderText = "SITE"
site_field.DataField= dt["extracol"]

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Richard GouetteIT ManagerAuthor Commented:
is dt a DataTable?
I do not have any DataTables in the project
Richard GouetteIT ManagerAuthor Commented:
I added 'siteName' as site_Name to my query, and this to my GridView definition:
                    <asp:BoundField DataField="site_Name" HeaderText="SITE" SortExpression="SITE"/>

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at runtime I'm getting:
That column should be column#5
so, I'm trying:
  GridView1.Rows(i).Cells(5).Text = "MEEEE"

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inside of my For loop through the rows.. but I get what you see in the picture

Seems like we're a step closer maybe..
Richard GouetteIT ManagerAuthor Commented:
All set. I got it working: part of the problem was using the wrong cell index# during testing.
I'm using the newly created field in SQL query, and:
        Dim site_Name As New BoundField() 'site_Name
        site_Name.HeaderText = "SITE"
        site_Name.DataField = "site_Name"

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