1. What tells you that you had to sum up the value to see if you can get closer to such value. Is there some experienced trick in trying to sum up to meet the 174?
I.E 64+64=128, 8+8+8+8+8+8+8+8+8+8+8= 88. What do you do with this information. I do not see the 128 or 88 applying in either of the two examples. You say 88 is the best match to create the network, but how does it do that? Or how does the 128 match with the subnet range?
Like I said before I can do it the old fashioned paper and pencil way but it takes me a long time to check then double check and triple check my work
"Since I knew the value of my last octet which was equal to 128 I proceed to sum up 128 and gives me a total of 256.
128 is lower than 174 therefore I had to sum up the same value to see if I can get closer to such value. because the fact I couldn't get closer. the value remains as 128 because it belongs to the range of the network 128+128=256."
1. What tells you that you had to sum up the value to see if you can get closer to such value. Is there some experienced trick in trying to sum up to meet the 174?
2. I assume you chose the 174 because it was the third octet, which is the same as where the 1=Network meets the 0=Host on the subnet mask. Also, what values would you be using to try to reach that number from 128 to 174? The predetermined bit value for each in the 128 64 32 16 8 4 2 1, for example 128+64, 128+32, 128+16 etc?
3. Lastly, what happens if you could find a value that gets closer to 174, what change would that make?
@Don I appreciate you taking the time to share that information with me. I have been hitting the Examcompass website for those. Like I said before I can do it the old fashioned paper and pencil way but it takes me a long time to check then double check and triple check my work which I am afraid may cripple me on the test since I only get a crappy marker and dry eraser board lol.