How to pass result of select query to Image.open()

I had this question after viewing Inserting dir/filename to mysql from Python.
I retrieve all the paths of the images from the database but now i am stuck to pass the paths to Image.open() to open the images and show them because the query result for single image is:D:\\Final\\Sample Pictures\\Lighthouse.jpg
Aqsa SamreenAsked:
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Flabio GatesCommented:
Because somebody told you to double your backslashes unnecessarily.
You only needed to change your call to os.walk from
    for root, dirs, files in os.walk("L:\Preservation\", topdown=False):
to
    for root, dirs, files in os.walk(r"L:\Preservation", topdown=False):
The replace
    fnameT = fname.replace('\\', '\\\\')
was totally unnecessary.

Anyway, since you already have doubled backslashes in your database table, your only option is to undo the doubling
i.e., s = s.replace('\\\\', '\\')
where s holds the result of your query.

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Flabio GatesCommented:
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