troubleshooting Question
How can i combine an IN and a LIKE statement in mysql query?
Nemetona asked on
MySQL 5.5.54
I have two tables, both with the same structure. I want to select records from table 1 based on the values in table 2.
I have a field, thevalue, which contains values such as:
181-1-0001
181-1-0002
181-2-0001
181-2-0004
I have the query:
SELECT * FROM table1 where thevalue in(SELECT distinct concat('Like ''',left(rangeid,8),'%''')
when I run this query I don't get an error but 0 rows are returned. when I run the inner select statement separately it returns
'Like \'181-1-00%\''
'Like \'182-1-00%\''
'Like \'183-2-00%\''
'Like \'187-2-00%\''
'Like \'188-2-00%\''
Can anyone suggest how I can return the rows in table1 where the first 8 characters of the thevalue field match those in the thevalue field of table2?
I have two tables, both with the same structure. I want to select records from table 1 based on the values in table 2.
I have a field, thevalue, which contains values such as:
181-1-0001
181-1-0002
181-2-0001
181-2-0004
I have the query:
SELECT * FROM table1 where thevalue in(SELECT distinct concat('Like ''',left(rangeid,8),'%''')
when I run this query I don't get an error but 0 rows are returned. when I run the inner select statement separately it returns
'Like \'181-1-00%\''
'Like \'182-1-00%\''
'Like \'183-2-00%\''
'Like \'187-2-00%\''
'Like \'188-2-00%\''
Can anyone suggest how I can return the rows in table1 where the first 8 characters of the thevalue field match those in the thevalue field of table2?
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