troubleshooting Question

json decode example

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gudii9Flag for United States of America asked on
Programming.NET ProgrammingJavaScriptProgramming Languages-OtherJSON
3 Comments1 Solution205 ViewsLast Modified:
The following example makes use of JSONObject and JSONArray where JSONObject is a java.util.Map and JSONArray is a java.util.List, so you can access them with standard operations of Map or List.

import org.json.simple.JSONObject;
import org.json.simple.JSONArray;
import org.json.simple.parser.ParseException;
import org.json.simple.parser.JSONParser;

class JsonDecodeDemo {

   public static void main(String[] args){
      JSONParser parser = new JSONParser();
      String s = "[0,{\"1\":{\"2\":{\"3\":{\"4\":[5,{\"6\":7}]}}}}]";
         Object obj = parser.parse(s);
         JSONArray array = (JSONArray)obj;
         System.out.println("The 2nd element of array");

         JSONObject obj2 = (JSONObject)array.get(1);
         System.out.println("Field \"1\"");

         s = "{}";
         obj = parser.parse(s);

         s = "[5,]";
         obj = parser.parse(s);

         s = "[5,,2]";
         obj = parser.parse(s);
      }catch(ParseException pe){
         System.out.println("position: " + pe.getPosition());
On compiling and executing the above program, the following result will be generated −

The 2nd element of array

Field "1"

i am not clear on above example. is it converting java object to json object?

what is meaning of decode
please advise
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