How can I get just the filename of the originating document?

How can I get just the filename of the originating document?
$ref=@$_SERVER[HTTP_REFERER]; gives me the full http path
$ref=@$_SERVER[REQUEST_URI]; gives me the /directoryname/filename
I only want the filename. Nothing else.
Can you help?
Thanks
Sas

PHP

Last Comment

Dave Baldwin

8/22/2022 - Mon

Dave Baldwin

12/3/2017

On many servers, 'SCRIPT_NAME' gives you just the filename. However, this is not guaranteed. Each server and admin may provide a different set of values because they all come from the server.

http://php.net/manual/en/reserved.variables.server.php

I use this program to see what my servers provide.

<!DOCTYPE HTML PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN"
 "http://www.w3.org/TR/html4/loose.dtd">

<html>
<head>
<title>PHP Server Variables</title>
</head>
<body>
<h1>PHP Server Variables</h1>
<?php

//reset($_SERVER);
foreach($_SERVER as $key => $value) {
    echo "<b>$key :</b> $value<br />\n";
}
?>
</body>
</html>

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sasnaktiv

12/3/2017

ASKER

Thanks for your quick response Dave,
Your list gives me a lot of information that I'm not looking for.
And it doesn't give me the simple, isolated filename that I am looking for.
I just want the 'filename' not its directory, not its path.
Can you isolate the 'filename'?
Sas

Dave Baldwin

12/3/2017

Apparently not.

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sasnaktiv

12/3/2017

ASKER

So much for PHP.
Do you know how I can delete everything before the 'filename'?
That might be a solution.
Thanks for the help, Dave

ASKER CERTIFIED SOLUTION

Dave Baldwin

12/3/2017