find the error code given by python and then put it in the except case

i want know how do it ? is it possible write it to file and i look at it later ?
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Shaun VermaakTechnical SpecialistCommented:
You can use
except Exception as e: print(e)

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yoy can reassign sys.excepthook to a function, that will be called foer any uncaught exception:

#!/usr/bin/env python
import sys

def func_that_fails(a, b):
    print("now I'll try to divide %d by %d" % (a,b))
    return a/b

def somedivisions():
    for a in range(10):
        b = 5 -a
        print("%d / %d = %f" % (a, b, func_that_fails(a, b)))

def my_exception_handler(exctype, value, tb):
    import traceback
    error_message = ''.join(traceback.format_tb(tb))
    error_message += "\n%s: %s\n" % (exctype, value)
    # comment this line if you want the error just in the file
    with open("myerror.log", "w") as fout:

sys.excepthook =my_exception_handler

if __name__ == "__main__":

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You can also explicitely try: / except:  the main function call.
Or you can (if you use it already) use python's logging module in combination with sys.excepthook to log the exceptions into your already existing log file.
Some more comments:

Above solution will always log an error and an exception if you stop your program with ctrl-C or if you kill it.
If that's an issue, then you can specifically exclude KeyboardInterrupt and SystemExit

Above solution has also solutions with multithreaded applications.
Exceptions in a thread will unfortunately not be caught by sys.excepthook

However there are some potential tricks / hacks, which might help you in such cases
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