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MS Access - Error 2447: There is an invalid use of the .(dot) or ! operator or invalid parentheses
Hi,
Attach is a sample DB. frmFirst is the first to open and then click Edit Record where Source field click that go to Search Source and then click on Add Source there the error is.
In Add Record it is working but in Edit Record is the one where ahead it gives error, any help how to resolve this?
Thank you.
Wsm93--1-.accdb
Attach is a sample DB. frmFirst is the first to open and then click Edit Record where Source field click that go to Search Source and then click on Add Source there the error is.
In Add Record it is working but in Edit Record is the one where ahead it gives error, any help how to resolve this?
Thank you.
Wsm93--1-.accdb
it seems that you're replicating your forms...
one quick resolution is to change:
to:
one quick resolution is to change:
If Me.txtAddRec = "Cap" Then
to:
If Me.txtAddRec1 = "Cap" Then
ASKER
how to resolve this #Name? things?
I am not able to solve this, is there a way to solve this?
I am not able to solve this, is there a way to solve this?
ASKER
it seems that you're replicating your forms...
one quick resolution is to change:
If Me.txtAddRec = "Cap" Then
Select all
Open in new window
to:
If Me.txtAddRec1 = "Cap" Then
both are different textboxes, if Source Search form open from add record it will pass value back to add record form and if it open from edit record form it will pass value back to edit record, that's the logic behind this.
how to resolve this #Name? things?you getting the error because you're referring to [Forms]![Table1]![txtAdd] while the fact that [Forms]![Table1] is yet not opened
I am not able to solve this, is there a way to solve this?
ASKER
is there a way to code that if the form is not open it can go to else condition or something?
i try the code that if Me.txtAddRec = "#Name?" then
do nothing
...
but that's also not working.
i try the code that if Me.txtAddRec = "#Name?" then
do nothing
...
but that's also not working.
ASKER CERTIFIED SOLUTION
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ASKER
Can you try implementing this in the sample db i have provided? because i am getting a lot of error and my db starts crashing with this function.
SOLUTION
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ASKER
it is working for Add Record but it is not working for Edit Record in the sample DB you provided.i try the same in edit record but it's not working,any idea?
how you defined as "not working"?
I tried the Edit Record button and at least it get rid of that #Name? error.
I tried the Edit Record button and at least it get rid of that #Name? error.
ASKER
#Name? error is not there but it is not passing value also, instead #Name? , yourDefaultValue is there, this is what i mean not working like the edit record is still not passing value back.
just do a message out and see what you getting here?
...
MsgBox Me.txtAddRec
If Me.txtAddRec = "Cap" Then
...
ASKER
Ryan, it's not about txtAddRec as that is working fine , it's about txtAddRec1 which is not working.
SOLUTION
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ASKER
Yes exactly.i use the similar method as you can see in image 3, but Add Source button is not working as by not working i mean it;s not passing value back to edit form, any idea why? neither now it's not showing any error also.
It would be helpful if you can make this work in the sample DB attach, then i will implement that in my operational database.
IMAGE1.png
IMAGE2.png
IMAGE3.png
It would be helpful if you can make this work in the sample DB attach, then i will implement that in my operational database.
IMAGE1.png
IMAGE2.png
IMAGE3.png
check your codes if below is correct...
>> ElseIf Me.txtAddRec1 = "CapEdit" Then
but value of txtAddRec1 is Cap1
hence nothing will be executed.
Private Sub Command167_Click()
If Me.txtAddRec = "Cap" Then
Forms!Table1!Source = Me.txtCap
DoCmd.Close
ElseIf Me.txtAddRec1 = "CapEdit" Then
Forms!Table1_1!Source = Me.txtCap1
DoCmd.Close
End If
End Sub
>> ElseIf Me.txtAddRec1 = "CapEdit" Then
but value of txtAddRec1 is Cap1
hence nothing will be executed.
ASKER
Thank you Ryan, you were right i was writing the wrong text "CapEdit", it started working in my database, thank you again.
Open in new window
(you can find that in Control Source)and there's an error returned with
Open in new window
you got to resolve that first.