asked on
please help me to solve the question i cant able to get the logic behind this question
Given two strings, base and remove, return a version of the base string where all instances of the remove string have been removed (not case sensitive). You may assume that the remove string is length 1 or more. Remove only non-overlapping instances, so with "xxx" removing "xx" leaves "x".
withoutString("Hello there", "llo") → "He there"
withoutString("Hello there", "e") → "Hllo thr"
withoutString("Hello there", "x") → "Hello there"
Java
Last Comment
CEHJ
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ASKER
thank you very much it_saige
FYI you can do it in one line with one method of String
True, they can, but something tells me that their instructor is looking for a loop based implementation.
-saige-
-saige-
Take a look at the replaceAll method for strings.
Do you plan on closing any of your other similar open questions, or are you going to ask your way merrily through the entire Codingbat range?
ASKER
Sir how to close the question sir
ARE you trying to troll us?
ASKER
No am new to this forums honestly don't know how to close it
You were already given a link to that procedure in one of your earlier questions.
ASKER
Sorry sir please give me the link sir
Err . . .
Why in the world would codingbat provide such a ridiculous method of looping through a string, comparing characters and length as a solution when the solution is as simple as -
public String withoutString(String str, String remove) {
return str.removeAll(remove,"");
}
???
public String withoutString(String str, String remove) {
return str.removeAll(remove,"");
}
???
Probably because there is no such method as removeAll. But maybe also because replaceAll doesn't work either.
krakata,thanks for pointing out my error. Forgive me for the use of removeAll when I meant replaceAll, but that does seem to work. In what case does it not?
Well, you can try it yourself, and satisfy yourself that the code is input as you intended rather than triangulate the matter through me as I may not have understood your intention.
I did try it before I even posted my comment with the following results:
replaceAll("Hello there","llo") ==> "He there"
replaceAll("Hello there", "e") ==> "Hllo thr"
replaceAll("Hello there", "x") ==> "Hello there"
replaceAll("xxx","xx") ==> "x"
replaceAll("Hello there","llo") ==> "He there"
replaceAll("Hello there", "e") ==> "Hllo thr"
replaceAll("Hello there", "x") ==> "Hello there"
replaceAll("xxx","xx") ==> "x"
Hint folks: the codingbat problem is case-insensitive
Those are not the results I get. Your code obtains the following afaics :
![withoutString results]()
Hint folks: the codingbat problem is case-insensitive
CEHJ sir,
Don't quite follow you - - - codingbat supplies the String and the element to remove. I can't see anywhere the cases are exposed to us?
Unless you mean that replaceAll uses regex . . . but that doesn't really help, or does it?
Thanks, CEHJ. It always helps to read the question carefully. To make the replacement case insensitive, add the case regex insensitive prefix -
public String withoutString(String str, String remove) {
return str.replaceAll("(?I)" + remove,"");
}
public String withoutString(String str, String remove) {
return str.replaceAll("(?I)" + remove,"");
}
Forgive EE's attempts at being helpful "(?I)" was meant to be "(?i)" with a lowercase letter i.
... was meant to be "(?i)" with a lowercase letter i.Yes, that was my solution as well ;)