balram sah
asked on
Warning: mysqli_num_rows() expects parameter 1 to be mysqli_result, boolean given in
$check_email="select * form users where user email='$email'";
$run_email = mysqli_query($con,$check_e
$check = mysqli_num_rows($run_email
if($check==1){
echo "<script>alert('Email phone already exit,please try another!')</script>";
exit();
$run_email = mysqli_query($con,$check_e
$check = mysqli_num_rows($run_email
if($check==1){
echo "<script>alert('Email phone already exit,please try another!')</script>";
exit();
your select statement got error...
>> $check_email="select * form users where user email='$email'";
is "user email" a single field? if yes, then you should try:
or make necessary adjustment there
>> $check_email="select * form users where user email='$email'";
is "user email" a single field? if yes, then you should try:
$check_email="select * form users where `user email`='$email'";or make necessary adjustment there
You did not check if the query was successful.
If it was not, then $run_email contains "FALSE".
HTH,
Dan
If it was not, then $run_email contains "FALSE".
HTH,
Dan
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Same effect + must simpler to understand.
Be sure to add in error checking after each mysql API call too.