Unix command to replace double quote with single quote on a specific line within a file

Need command to replace " with ' within a specific line within a file.
iBincAsked:
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Joy DingenenICT system consultantCommented:
sed and awk can do this:

sed 'line#s/\"/\'/'

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or
oh god my awk is rusty but here goes
awk "NR==line# {sub(/\"/, \"'\"); print}"

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if you don't know how to use sed and awk:
https://en.wikipedia.org/wiki/Sed
https://en.wikipedia.org/wiki/AWK

if it's 1 time in 1 file you could also vi the file and
:line# s/\"/\'/g
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Hanno P.S.IT Consultant and Infrastructure ArchitectCommented:
If there is more than one " to be replaced, use this sed statement (add the g):
sed 'line#s/\"/\'/g'
a) Remember to escape the quotes with backslash
b) To run it on a file, this is the command to use:
    cat filename | sed 'line#s/\"/\'/g' > filename.out
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iBincAuthor Commented:
thanks...
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Joy DingenenICT system consultantCommented:
Topic inactive
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