Hi

I have a formula that works perfectly, however I need to add two conditions and I got a bit lost.
here is the formula
IF(P15>Q\$13,SQRT(P15-P\$13)+((F16*P15)/P\$13),
((F16*P15)/P\$13))/2.5
I've shown the two conditions on two lines for easier identification.
You can see there are two conditions
The extra two conditions I would like to add to both of the above two conditions
1)  IF(F60>50
2) AND(H16<1.1
Return zero if both conditions qualify. I want to apply to both of the conditions in the formula.
Thanks
Ian
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Commented:
Use this
IF(AND(F60>50,H16<1.1),0,
IF(P15>Q\$13,SQRT(P15-P\$13)+((F16*P15)/P\$13),
((F16*P15)/P\$13))/2.5 )

F60 is empty, so I guess it should be F16 and not F60, and then it is
=IF(AND(F16>50,H16<1.1),0,IF(P15>Q\$13,SQRT(P15-P\$13)+((F16*P15)/P\$13),((F16*P15)/P\$13))/2.5)
1

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retiredAuthor Commented:
Hi Ejgil, it works fine thank you. Can I ask one more add on and that is either condition result should not exceed
a value of 1000. If result exceeds 1000 then 1000 otherwise etc. To be applied to both conditions
Thanks if you can help.
Ian
0
retiredAuthor Commented:
please ignore last request and modify original formula below to give a max result of 1,000 for both conditions
Thanks

IF(P15>Q\$13,SQRT(P15-P\$13)+((F16*P15)/P\$13),
((F16*P15)/P\$13))/2.5
0
retiredAuthor Commented:
This was my best effort but is wrong :(

=IF(IF(P15>Q\$13,SQRT(P15-P\$13)+((F16*P15)/P\$13>1000,1000)),
IF(((F16*P15)/P\$13>1000,1000,((F16*P15)/P\$13))/2.5)

ps..... yes you were right about the F16 being correct cell... sorry
0
retiredAuthor Commented:
No reply yet from my extra request which I may ask again on a separate question.
However the original question was answered successfully- Well Done Ejgil
and will close the question shortly and award you full points. Thanks
Ian
0
Commented:
Try this
=IF(AND(F16>50,H16<1.1),0,IF(P15>Q\$13,IF(SQRT(P15-P\$13)+((F16*P15)/P\$13)>1000,1000,SQRT(P15-P\$13)+((F16*P15)/P\$13)),IF(F16*P15/P\$13>1000,1000,F16*P15/P\$13))/2.5)
1
retiredAuthor Commented:
That's great, Thanks
0
retiredAuthor Commented:
Thanks Ejgil, your expert solution was much appreciated.
HNY   Ian
0
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