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Excel formula - Find column letter from another sheet based on the header name from specific row


I need your help with an excel formula that would retrieve the column letter from another sheet inside the same workbook that have specific header name.

Let me explain;

In the workbook, i have 2 sheets: Test1 and Dbase.

Sheet Test1 will have headers that could start at any rows. In below case, the header are at row 4.
Test1 sheet sample

Then I have the Dbase sheet that will have the same header names in column B, I will tell also the sheet name that I want to pull the column letter from in column D, and also the Row headers in column E where the headers are positioned in the sheet from the column D.
Dbase sheet sample
Now, I want to have a formula in column C that will pull the column letters for each headers.
The result will look like this:
Final result

I have some formulas like : SUBSTITUTE(ADDRESS(1,COLUMN(),4,”1”,””) and also UPPER(CHAR(COLUMN()+96)), but this is only applicable when retrieving from the same sheet.

How can I do this?

Thank you for your help.
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1 Solution
NorieVBA ExpertCommented:
You could use this to get the column numbers for the headers on the other sheet,

=MATCH(B2, INDIRECT("'" & D2 & "'!"&E2&":"&E2), 0)

and to get the column letters.

=UPPER(CHAR(MATCH(B2, INDIRECT("'" & D2 & "'!"&E2&":"&E2), 0)+96))

Note the 2nd formula is basically UPPER(CHAR(COLUMN()+96)) with COLUMN() replaced with the first formula.
Wilder1626Author Commented:
Hi Norie

When trying the formula. i'm getting a "We found a problem with this formula" error. was it working on your side?
NorieVBA ExpertCommented:
I copied the formulas directly from Excel where they are both working.

I'll copy them again.

Column number: =MATCH(B2, INDIRECT("'" & D2 & "'!"&E2&":"&E2), 0)

Column letter:    =UPPER(CHAR(MATCH(B2, INDIRECT("'" & D2 & "'!"&E2&":"&E2), 0)+96))
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Wilder1626Author Commented:
for some reason, i'm still having the same error. can you please send me the sample with your formula in it?
NorieVBA ExpertCommented:
Here's another formula that handles there being more than one column letter.

NorieVBA ExpertCommented:
Wilder1626Author Commented:
The formula is working:

Thank you for your help
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