# Delete an entire row based on a condition value in one of the columns in the row

I have a row of data/  in one cell i set up a match condition, so if it is equal to zero i want to delete the row and keep deleting until all rows that have dont match are deleted and subsequent matching rows move up to line up consecutively.
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Senior Software EngineerCommented:
Try this
``````Sub DeleteRow()
Dim lRow As Long
Dim iCntr As Long
lRow = 390
For iCntr = lRow To 1 Step -1
If Cells(iCntr, 5).Value = "none" Then // change this condition as per need
Rows(iCntr).Delete
End If
Next
End Sub
``````
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Author Commented:
Sorry I'm new to using VBA.  So suppose i want to loop thru based on a column F values = 0 than delete.  The code you provided in RED,  i put value = 0 there but how do i set the column there?

thanks
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Commented:
So suppose i want to loop thru based on a column F values = 0 than delete.
you can customize what Dorababu posted to something like this:

``````Sub test()
Dim LastRow As Integer

If MsgBox("Are you sure want to delete the rows?", vbExclamation + vbYesNo, "Delete rows?") = vbYes Then
LastRow = Cells(Rows.Count, "F").End(xlUp).Row
For i = LastRow To 2 Step -1 'Assuming got header
If Cells(i, "F") = 0 Then
Rows(i).Delete
End If
Next
End If
End Sub
``````
29077749.xlsm
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Author Commented:
Thank you will give this a go!
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Commented:
any test results so far?
0
Commented:
as proposed
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