asked on

I upload file from directory to database but i realise that all file i upload is the same.

How to fix this .. can upload the directory but all the csv file content i upload was the same file ..
Actually there are 30 files , but one file uploaded 30 times.
Here are my code for upload part .. upload.php

<?php
include 'config.php';

if(isset($_POST['btn-upload']))
{    
  $log_directory = '/xampp/htdocs/mydoc';
  $results_array = array();

        if ($handle = opendir($log_directory))
        {
                while(($file = readdir($handle)) !== FALSE)
                {
                    if ($file != "." && $file != "..") {
                        $results_array[] = $file;
                    }
                }
                closedir($handle);
        }

  //Output findings
  foreach($results_array as $value)
{
 $csvMimes = array('text/x-comma-separated-values', 'text/comma-separated-values', 'application/octet-stream', 'application/vnd.ms-excel', 'application/x-csv', 'text/x-csv', 'text/csv', 'application/csv', 'application/excel', 'application/vnd.msexcel', 'text/plain');
    if(!empty($_FILES['file']['name']) && in_array($_FILES['file']['type'],$csvMimes)){
        if(is_uploaded_file($_FILES['file']['tmp_name'])){
            
            //open uploaded csv file with read only mode
            $csvFile = fopen($_FILES['file']['tmp_name'], 'r');
            
            //skip first line
            fgetcsv($csvFile);
            
            //parse data from csv file line by line
            while(($line = fgetcsv($csvFile)) !== FALSE){
                 //insert member data into database
                    $db->query("INSERT INTO nov(f_name,name, cpu_count, memory_size, disk_space_size, nic_count, power_state) VALUES ('".$value."','".$line[0]."','".$line[1]."','".$line[2]."','".$line[3]."','".$line[4]."','".$line[5]."')");
                }
            }
            			
            //close opened csv file
            fclose($csvFile);


        


 if(move_uploaded_file)
 {
	 
 ?>
  <script>
  alert('successfully uploaded');
        window.location.href='index.php?success';
        </script>
  <?php
 }
 else
 {
  ?>
  <script>
  alert('error while uploading file');
        window.location.href='index.php?fail';
        </script>
		
  <?php
 }
}
}
}

?>

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Julian Hansen

I am guessing you used a multiple file input but did not specify an array as the name for the control

In other words

<input type="file" multiple" name="file">

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Instead of

<input type="file" multiple" name="file[]">

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Note the [] on the end of the name - this will create names for the uploaded files that PHP will translate into an array.

Post your HTML form so we can see how you have implemented that.

If you use the above you will get a response that looks something like this

$_FILES
   name: Array()
      0 => Filename1.csv
      1 => Filename2.csv
      ...
    tmp_name: Array()
      0: d9dwe99x.tmp
      1: eix9d9b9d.tmp
       ...
     size: ...

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In other words an array of N items for each of the attributes for a file upload - where N is the number of files uploaded.

You will then need to create a loop that operates on these arrays - checking the file is uploaded and then moving / renaming them to their new location before updating the DB.

Post your <form> code so I can confirm the above.

Yong Scott

ASKER

<?php
include 'config.php';
?>
<!DOCTYPE html>
<html>
<head>
<title>File Uploading With PHP and MySql</title>

<link rel="stylesheet" href="style.css" type="text/css" />
</head>
<body>
<div id="header">
<label>File Uploading With PHP and MySql</label>
</div>
     <br /><br />
   <form action="index.php" method="post" enctype="multipart/form-data">
   <button type="submit" name="btn-main" style="height: 25px; width: 200px">MAIN PAGE</button>
    </form>

<div id="body">

<table style = "border-collapse:collapse">
    <tr>

    </tr>
    <tr>
                <thead>
                    <tr>
					  <th style = "width:20px;border:1px solid black" align = "center">Date</th>
                      <th style = "width:20px;border:1px solid black" align = "center">File Name</th>
                      <th style = "width:20px;border:1px solid black" align = "center">Site</th>					  
                      <th style = "width:20px;border:1px solid black" align = "center">Name</th>
                      <th style = "width:20px;border:1px solid black" align = "center">CPU Count</th>
                      <th style = "width:20px;border:1px solid black" align = "center">Memory Size</th>
                      <th style = "width:20px;border:1px solid black" align = "center">Disk Space Size</th>
                      <th style = "width:20px;border:1px solid black" align = "center">NIC Count</th>
					  <th style = "width:20px;border:1px solid black" align = "center">Power State</th>
                      <th style = "width:20px;border:1px solid black" align = "center">Memory Size(inGB)</th>
					  <th style = "width:20px;border:1px solid black" align = "center">Disk Space Size(inGB)</th>
                    </tr>
                </thead>
                <tbody>
                <?php
                    //get records from database
                    $query = $db->query("SELECT * FROM nov");
                    if($query->num_rows > 0){ 
                        while($row = $query->fetch_assoc()){ ?>
                    <tr>

                      <td style = "width:20px;border:1px solid black" align = "center"><?php echo date('m-d-y', strtotime($row['date'])); ?></td>	
					  <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['f_name']; ?></td>	
					  <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['site']; ?></td>					  
                      <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['name']; ?></td>
                      <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['cpu_count']; ?></td>
                      <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['memory_size']; ?></td>
                      <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['disk_space_size']; ?></td>
					  <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['nic_count']; ?></td>
					  <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['power_state']; ?></td>
					  <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['memory_size_ingb']; ?></td>
					  <td style = "width:20px;border:1px solid black" align = "center"><?php echo $row['disk_space_size_ingb']; ?></td>
                      
                    </tr>
                    <?php } }else{ ?>
                    <tr><td style = "width:20px;border:1px solid black" align = "center" colspan="12">No data(s) found.....</td></tr>
                    <?php } ?>
 
    </table>
    

</div>
</body>
</html>

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Yong Scott

ASKER

That is my html code

Yong Scott

ASKER

Do you know how to not target directory can upload file which mean all directory can access no specific directory?

Julian Hansen

Where is your file input control?

Yong Scott

ASKER

   <font size="5">Directory Upload</font>
      <br /><br />
 <form action="upload.php" method="post" enctype="multipart/form-data">
 <input type="file" webkitdirectory mozdirectory  name="file"  />
 <button type="submit" name="btn-upload" style="height: 25px; width: 100px">UPLOAD</button>
 </form>

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Julian Hansen

webkitdirectory and mozdirectory are non-standard attributes - they are not part of the HTML5 standard and are not supported in all browsers.

Do you know how to not target directory can upload file which mean all directory can access no specific directory?

I have no idea what this is saying

Yong Scott

ASKER

webkitdirectory and mozdirectory are non-standard attributes - they are not part of the HTML5 standard and are not supported in all browsers.

Its can work in my browser , only problem is the directory file uploaded but all file is the same

Yong Scott

ASKER

Actually I want to upload folder that contains of csv files , but the files have different data inside , so how can I display it all

Yong Scott

ASKER

Unfortunately, it only works for a single file insertion. I have further tried to edit it, but it just inserts the last file that is in the directory. Any help will be much appreciated.

Julian Hansen

Where is your code that iterates over the files variable to get all the files and save them
When you submit multiple files they are put in an array that looks like this

Array
(
  [files] => Array
    (
      [name] => Array
        (
          [0] => 01.csv
          [1] => 02.csv
          [2] => 03.csv
          [3] => 04.csv
          [4] => 05.csv
        )
      [type] => Array
        (
          [0] => application/vnd.ms-excel
          [1] => application/vnd.ms-excel
          [2] => application/vnd.ms-excel
          [3] => application/vnd.ms-excel
          [4] => application/vnd.ms-excel
        )
      [tmp_name] => Array
        (
          [0] => C:\Windows\Temp\php5FEB.tmp
          [1] => C:\Windows\Temp\php5FEC.tmp
          [2] => C:\Windows\Temp\php5FED.tmp
          [3] => C:\Windows\Temp\php5FEE.tmp
          [4] => C:\Windows\Temp\php5FEF.tmp
        )
      [error] => Array
        (
          [0] => 0
          [1] => 0
          [2] => 0
          [3] => 0
          [4] => 0
        )
      [size] => Array
        (
          [0] => 170516
          [1] => 116832
          [2] => 2351
          [3] => 275819
          [4] => 1870
        )
    )
)

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I have already given you the process for iterating over this array in this comment (in your other question)
https://www.experts-exchange.com/questions/29078470/How-to-import-directory-and-echo-the-filename.html?anchorAnswerId=42435985#a42435985

Yong Scott

ASKER

Array
(
[files] => Array
(
[name] => Array
(
[0] => 01.csv
[1] => 02.csv
[2] => 03.csv
[3] => 04.csv
[4] => 05.csv
)
[type] => Array
(
[0] => application/vnd.ms-excel
[1] => application/vnd.ms-excel
[2] => application/vnd.ms-excel
[3] => application/vnd.ms-excel
[4] => application/vnd.ms-excel
)
[tmp_name] => Array
(
[0] => C:\Windows\Temp\php5FEB.tmp
[1] => C:\Windows\Temp\php5FEC.tmp
[2] => C:\Windows\Temp\php5FED.tmp
[3] => C:\Windows\Temp\php5FEE.tmp
[4] => C:\Windows\Temp\php5FEF.tmp
)
=> Array
(
[0] => 0
[1] => 0
[2] => 0
[3] => 0
[4] => 0
)
[size] => Array
(
[0] => 170516
[1] => 116832
[2] => 2351
[3] => 275819
[4] => 1870
)
)
)

So I need list down the file for each array?
something like this :
[0] => file1.csv
[1] => file2.csv
[2] => file3.csv
[3] => file4.csv
[4] => file5.csv
Until file30.csv?

ASKER CERTIFIED SOLUTION

Julian Hansen

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Yong Scott

ASKER

Im sorry Julian not so understand ur coding :(

Julian Hansen

What don't you understand?

Yong Scott

ASKER

I tried to implement your coding ..

<?php
include 'config.php';


if(isset($_POST['btn-upload']))
{  


$targetDir = "uploads/";
$files = $_FILES['file']
foreach($files['name'] as $key => $name) {
    $file = $files['tmp_name'][$key];
    $target = $targetDir  . "/" . $name;
    if (is_uploaded_file($file)) {
       move_uploaded_file($file, $target);
echo $file . '</br>';
   
    }
}
}

?>

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I not sure is it the right way , but the output get error .

Parse error: syntax error, unexpected 'foreach' (T_FOREACH) in C:\xampp\htdocs\db_v3\upload.php on line 11

Julian Hansen

You are missing a ';' on line 10

$files = $_FILES['file']

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Should be

$files = $_FILES['file'];

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Yong Scott

ASKER

Parse error: syntax error, unexpected 'foreach' (T_FOREACH) in C:\xampp\htdocs\db_v3\upload.php on line 11
still have this error

Julian Hansen

Please don't post errors without the accompanying source code. I have no idea what your code now looks like and the error on its own is of no use.

Yong Scott

ASKER

<?php
include 'config.php';


if(isset($_POST['btn-upload']))
{  


$targetDir = "uploads/";
$files = $_FILES['file'];
foreach($files['name'] as $key => $name) {
    $file = $files['tmp_name'][$key];
    $target = $targetDir  . "/" . $name;
    if (is_uploaded_file($file)) {
       move_uploaded_file($file, $target);
echo $file . '</br>';
   
    }
}
}

?>

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This my coding

Yong Scott

ASKER

$targetDir = "uploads/";

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anyway the "uploads/" is nid to set path ?

Yong Scott

ASKER

Thank Julian Hansen ! I tried your code and success already

Julian Hansen

You are welcome.