batch findtext

I have the following batch file.

@echo off

set hour=%time:~0,2%
if "%hour:~0,1%" == " " set hour=0%hour:~1,1%
echo hour=%hour%
set min=%time:~3,2%
if "%min:~0,1%" == " " set min=0%min:~1,1%
echo min=%min%
set secs=%time:~6,2%
if "%secs:~0,1%" == " " set secs=0%secs:~1,1%
echo secs=%secs%

set year=%date:~-4%
echo year=%year%
set month=%date:~4,-8%
if "%month:~0,1%" == " " set month=0%month:~1,1%
echo month=%month%
set day=%date:~7,-5%
if "%day:~0,1%" == " " set day=0%day:~1,1%
echo day=%day%

set datef=%hour%-%day%-%month%-%year%
set dayf=%day%-%month%-%year%

echo datetimef=%datef%
echo %dayf%


set findtext=" DS-"
set findfile="Z:\OP\exa\02-04-18 - Copy.P02"

findstr %findtext% %findfile%

for /f "delims=" %%a in ('findstr %findtext% %findfile%') do echo %%a >> "Z:\OP\test-%month%-%year%.txt


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I however need to search for multiple criteria i need to find all instances of " DS-" and " DSA-" how do i search for both?
Who is Participating?
Bill PrewCommented:
If it's either, then you can do:

set findtext=/c:" DS-" /c:" DSA-"

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Bill PrewCommented:
Do you mean BOTH have to be present for a match, or EITHER?

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