How to find the time differences between successive rows?

The attached sample file contains different time entries from an Oracle DB for a day in the descending order. I am required to verify the time difference between all adjoining entries is 4 seconds. Can someone suggest which is the best way to find this?
Sample.xlsx
sukhoi35Asked:
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sdstuberCommented:
to see the values and the difference from prior value

SELECT *
  FROM (SELECT your_column, prev_value, NUMTODSINTERVAL(your_column - prev_value, 'day') diff
          FROM (SELECT your_column, LAG(your_column) OVER (ORDER BY your_column) prev_value FROM your_table));


To find the rows that differ by more than 4 seconds from prior value

SELECT *
  FROM (SELECT your_column, prev_value, NUMTODSINTERVAL(your_column - prev_value, 'day') diff
          FROM (SELECT your_column, LAG(your_column) OVER (ORDER BY your_column) prev_value FROM your_table))
 WHERE diff > INTERVAL '4' SECOND
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sukhoi35Author Commented:
Thank you very much!
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