Ms Excel: retrieve last numeric string after "\"char

Hello experts,

I have the following string C:\toto\titi\tt\3252.

I am looking for a formula in order to retrieve numeric value such as 3252. The complex thinks is that last numeric value doesn't always contains 4 number it can contains 5 or 6. The unique think which is always common is that the next  left value of numeric string to retrieve is \ char.

Thank you very much for your help.
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Martin LissOlder than dirtCommented:
I found this on the web.


I don't begin to understand it, but it does work.
Roy CoxGroup Finance ManagerCommented:
assuning string in A!, try

Martin LissOlder than dirtCommented:
I don't want any credit but Roy probably meant this.

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Roy CoxGroup Finance ManagerCommented:
Just trying to change it but you beat me Martin, I also meant "assuming" ( clumsy fingers!!!)
LD16Author Commented:
Tested but it doesn't work
Instead of having:

LD16Author Commented:
Thank you Martin. I tested and it works.
Thank you very much for your help.
Martin LissOlder than dirtCommented:
You’re welcome and I’m glad I was able to help.

If you expand the “Full Biography” section of my profile you’ll find links to some articles I’ve written that may interest you.

Marty - Microsoft MVP 2009 to 2017
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Rob HensonFinance AnalystCommented:
To explain the functions that Martin used:

The SUBSTITUTE function will look for specified characters and replace them with another specified character(s).

LEN function returns the number of characters in the string

REPT function repeats a character the specified number of times.

RIGHT function returns specified number of characters from the right hand end of the string.

TRIM function removes leading or trailing spaces and multiple central spaces get converted to a single space.

In this instance all of the occurrences of  \ are being replaced with a \ and repeated spaces, the space being repeated as many times as the ORIGINAL length of the string.

The RIGHT function is then looking at the right hand end of the amended string and returning the length of the original string; this will be the last characters and however many spaces it needs to be equivalent to the original length. The TRIM function then removes the surplus spaces.
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