Two case statements with a group by function

Two case statements with a group by function.  Is there a way I can do the following: it's falling over because the outer case doesn't need a group by but the inner case does.

                 
   SELECT LECTURE.COLLEGE_NO,
                                 CASE WHEN COLLEGE.TYPE = 1 THEN 'Fee Paying'
                                 WHEN COLLEGE.TYPE IN (2,3) THEN 
                                           CASE   WHEN COUNT (DISTINCT LECTURE_TYPE) = 1 THEN 'FREE'
                                           WHEN COUNT (DISTINCT LECTURE_TYPE) > 1 THEN 'FREE and FEE PAYING' END
                                 END ATT_SCHOOL_TYPE_CATEGORY 
                            FROM LECTURE, COLLEGE
                            WHERE LECTURE.COLLEGE_NO = COLLEGE.COLLEGE_NO
                            GROUP BY LECTURE.COLLEGE_NO

Open in new window



Basically is it's Fee paying use College Type but if it's free or free and fee paying use a count of lecture types to calculate the type of college

Any help would be greatly appeciated.
Coco BeansDesignerAsked:
Who is Participating?

[Product update] Infrastructure Analysis Tool is now available with Business Accounts.Learn More

x
I wear a lot of hats...

"The solutions and answers provided on Experts Exchange have been extremely helpful to me over the last few years. I wear a lot of hats - Developer, Database Administrator, Help Desk, etc., so I know a lot of things but not a lot about one thing. Experts Exchange gives me answers from people who do know a lot about one thing, in a easy to use platform." -Todd S.

OMC2000Commented:
You could add aggregative functions (min,max) to outer case:
   SELECT LECTURE.COLLEGE_NO,
                                 CASE WHEN max(COLLEGE.TYPE) = 1 THEN 'Fee Paying'
                                 WHEN min(COLLEGE.TYPE) IN (2,3) THEN 
                                           CASE   WHEN COUNT (DISTINCT LECTURE_TYPE) = 1 THEN 'FREE'
                                           WHEN COUNT (DISTINCT LECTURE_TYPE) > 1 THEN 'FREE and FEE PAYING' END
                                 END ATT_SCHOOL_TYPE_CATEGORY 
                            FROM LECTURE, COLLEGE
                            WHERE LECTURE.COLLEGE_NO = COLLEGE.COLLEGE_NO
                            GROUP BY LECTURE.COLLEGE_NO

Open in new window

0

Experts Exchange Solution brought to you by

Your issues matter to us.

Facing a tech roadblock? Get the help and guidance you need from experienced professionals who care. Ask your question anytime, anywhere, with no hassle.

Start your 7-day free trial
Coco BeansDesignerAuthor Commented:
Perfect and so simple!
0
It's more than this solution.Get answers and train to solve all your tech problems - anytime, anywhere.Try it for free Edge Out The Competitionfor your dream job with proven skills and certifications.Get started today Stand Outas the employee with proven skills.Start learning today for free Move Your Career Forwardwith certification training in the latest technologies.Start your trial today
SQL

From novice to tech pro — start learning today.