Return a row from query where keys are different from other rows in the same table

Hello guys

I have a table with some rows, I need to make a query where only the row that is diferent from must be return in my query

something like this the x.codprod='A1258'


select * from table01 a
inner join table01 b on (b.xname<>a.xname and b.xcoddep<>a.xcoddep and b.xcodprod<>a.xcodprod)

it should return me

create table table01 (
xname varchar(20),
xcoddep varchar(20),
xcodprod varchar(20)
)

insert into table01 (xname, xcoddep, xcodprod) values ('alexandre', '01452', 'A1257')
insert into table01 (xname, xcoddep, xcodprod) values ('alexandre', '01452', 'A1257')
insert into table01 (xname, xcoddep, xcodprod) values ('alexandre', '01452', 'A1257')
insert into table01 (xname, xcoddep, xcodprod) values ('alexandre', '01451', 'A1258')

select * from table01

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How to do that?
thanks
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hidrauAsked:
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PortletPaulfreelancerCommented:
are you certain you want ALL THREE columns different?

If you only want this row returned ('alexandre', '01451', 'A1258') then the xname is EQUAL to other rows.

Please try this query on a larger sample and let us know if it returns the wanted result or not.
select
      a.xname, a.xcoddep, a.xcodprod
from table01 a
left join table01 b on a.xname = b.xname
                    and a.xcoddep = b.xcoddep
                    and a.xcodprod = b.xcodprod
group by
      a.xname, a.xcoddep, a.xcodprod
having count(a.xcoddep) = 1 or count(a.xcodprod) = 1
;

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hidrauAuthor Commented:
thanks very very much
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Microsoft SQL Server 2008

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