nicky s

asked on 4/24/2018

Need Python Script for following requirement

Need Python script

Given a folder of build files that might look like this:

/Build-1.dmg
/Build-2.dmg
/Build-2.1.dmg
/Build-2.1.1.dmg
/Build-3.dmg
/Build-3.2.dmg
/Build-3.19.dmg

Write a script that takes a path to the folder as an argument, and prints the highest build number (just the number, i.e. 2.1.1)
Note: The first digit can go up to 999 and should always be present, but the second and third can only go up to 99, and might not be included.

Python

Last Comment

aikimark

8/22/2022 - Mon

Florian Lenschow

4/24/2018

Not to elegant, since some things are hard coded but this should do the trick:

import os

def get_max_build_number(folder):
	max_build_number = [0,0,0]
	for filename in os.listdir(folder):
		if filename.endswith('.dmg'):
			number = os.path.splitext(filename[6:])[0]
			nums = number.split('.')
			if len(nums) == 1:
				nums.extend([0,0])
			elif len(nums) == 2:
				nums.extend([0])
			if int(nums[0]) > max_build_number[0]:
				max_build_number[0] = int(nums[0])
				if int(nums[1]) > max_build_number[1]:
					max_build_number[1] = int(nums[1])
					if int(nums[2]) > max_build_number[2]:
						max_build_number[2] = int(nums[2])
	return '.'.join(str(x) for x in max_build_number)

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Also I would suggest to include zeros in the build names to make the naming convention a bit clearer.

aikimark

4/25/2018

why wouldn't it return 3.19?

aikimark

4/25/2018

I created some empty files with the sample names you provided and ran this code:

import os
files=[f for f in os.listdir('C:\Users\Mark\Downloads\Q_29096318')]
#print files
#print max(files)
print max([map(int,x[6:-4].split(".")) for x in files])

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It produced the following output:

[3, 19]

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Note: The two commented lines were there for diagnostic purposes. I needed to ensure that I was retrieving the file names and that the max() function returned incorrect results on string lists.

Your help has saved me hundreds of hours of internet surfing.

fblack61

Florian Lenschow

4/25/2018

aikimark's solution is more elegant. I haven't thought about using the max function so I compared the values manually, but I forgot another condition that resets the minor version numbers when a greater number is found in first position.

aikimark

4/25/2018

If you need to assemble the result of the max() function into a string, do something like this:

m = max([map(int,x[6:-4].split(".")) for x in files])
print '.'.join(str(x) for x in m)

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aikimark

4/25/2018

@nicky s

I'm awaiting your response to my question about the correct max version number of your posted sample. I can easily convert my code into a function, but I want to know that it is producing the correct output.

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nicky s

4/25/2018

ASKER

It should return, 3.19 for the below files.

/Build-1.dmg
/Build-2.dmg
/Build-2.1.dmg
/Build-2.1.1.dmg
/Build-3.dmg
/Build-3.2.dmg
/Build-3.19.dmg

aikimark

4/25/2018

import os

def get_max_build_number(folder):
    files=[f for f in os.listdir(folder)]
    m = max([list(map(int,f[6:-4].split("."))) for f in files])
    return '.'.join(str(x) for x in m)

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ASKER CERTIFIED SOLUTION

aikimark

5/3/2018

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